Page 286 - Theory and Problems of BEGINNING CHEMISTRY
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CHAP. 18]                           ORGANIC CHEMISTRY                                 275


               18.17. Condensed formulas for C 3 H 8 and C 2 H 4 are fairly easy to write. Explain why they would be harder to
                     write for C 4 H 10 and C 3 H 6 .
                     Ans.  These compounds can each form isomers (having the same molecular formulas). C 4 H 10 can occur as an
                           unbranched compound and a branched-chain compound. C 3 H 6 can occur with a double bond or in a ring.

               18.18. Explainwhytherecanbenotwo-carbonbranchinanalkanethatcontainsafour-carbonlongestcontinuous
                     chain.
                     Ans.  A branch cannot start at the end of a carbon chain, and so it must be from one of the two center carbon
                           atoms in the parent compound. If a two-carbon chain is added there, the two-carbon chain becomes part of
                           the longest chain, and a one-carbon side chain is left.
                                                                    C
                                                                          longest chain
                                                                    C
                                               Side chain        C  C   C   C


               18.19. Draw condensed formulas to represent the two isomers of butene which contain no branches.
                     Ans.   CH 3  CH 2  CH   CH 2                  CH 3  CH    CH   CH 3

               18.20. Which ones of the following are identical to each other?
                                      Br                Br                      Br                  Br
                                 C  C              C   C                  C   C                C  C
                           (a)  C     C       (b)  C     C  Br       (c)  C     C        (d)  C     C

                                 C  C              C   C                  C   C                C  C
                                      Br                                        Br           Br
                     Ans.  (a) and (c) are identical because the double bonds are really delocalized, (b) and (d) have the Br atoms on
                           different carbon atoms.

               18.21. Write condensed formulas for the four isomers of octane each of which contains three one-carbon
                     branches.
                                 CH CH 3                                CH 3      CH 3
                                    3
                     Ans.  CH 3  C   CH    CH 2  CH 3              CH 3  C  CH 2  CH    CH 3
                                 CH 3                                   CH 3

                                 CH 3  CH 3
                                                                      CH 3  CH 3  CH 3
                           CH 3  CH   C    CH 2  CH 3
                                                                CH 3  CH   CH    CH   CH 3
                                      CH 3

               RADICALS AND FUNCTIONAL GROUPS
               18.22. Is it true that isomers can occur only with hydrocarbons?

                     Ans.  No. Compounds with functional groups can form isomers even more extensively than can hydrocarbons
                           (given the same number of carbon atoms).

               18.23. List the pairs of organic functional groups that can be isomeric with each other if the numbers of carbon
                     atoms in their compounds are the same.

                     Ans.  Alcohols and ethers; aldehydes and ketones; acids and esters.
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