Page 119 - Semiconductor For Micro- and Nanotechnology An Introduction For Engineers
P. 119

The Electronic System
                                                             V 0  Vx()

                Figure 3.6. Barrier potential and
                sketched real part of a harmonic                                   x
                                                              0      a
                wavefunction hitting the barrier
                with energy E =  V ⁄  2  , i.e.,
                               0
                smaller than V 0  .



                                                     (
                                                  2mU –   E)
                                                       0
                                                                      ,
                                     λ =  ± k =  ±  ----------------------------- , for x ∈  [ 0 a]  (3.46b)
                                            II         2
                                                      —
                             There are no bound states in this case because the region where harmonic
                             solutions exist is infinite.  The states with energies  E >  U  0   show the
                             inverse behavior as for the box potential (3.25).  This is indicated in
                             Figure 3.6. Remember that there exist solutions that decay exponentially
                             inside the barrier and extend to infinity on either side of the barrier for
                             E <  U  0  .


                             We analyze this situation further. Consider a free electron impinging the
                             barrier from region I to have a definite wavevector  k  I  . Thus our trial
                             functions read

                                        ψ x() = a exp ( ik x) +  a exp  – (  ik x)  (3.47a)
                                                1
                                                            2
                                         I
                                                                    I
                                                       I
                                       ψ () = b exp  ( k x) +  b exp  k – (  x)  (3.47b)
                                           x
                                         II     1     II     2     II
                                       ψ () = c exp  ( ik x) +  c exp  – (  ik x)  (3.47c)
                                           x
                                         III     1     I     2      I
                             We assume the impinging wave to have unit amplitude (a =  1  ) and fur-
                                                                          1
                             ther that there is no wave travelling from region III towards the barrier
                             (c =  0  ). Note that  k =  k  . On either side of the barrier the condi-
                              2                I    III
                             tions for the continuity of the wavefunction  ψ   and its spatial derivative

                116          Semiconductors for Micro and Nanosystem Technology
   114   115   116   117   118   119   120   121   122   123   124