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The Electromagnetic System
                             4.2 Basic Description of Light
                             Around the beginning of the 20th century, new experimental evidence
                             indicated that light, when interacting with a solid material, seems to
                             behave also as a “particle” – now called a photon. Up to that stage, the
                             wave nature model of light had sufficed, and could be cleverly used to
                             explain most phenomena observed. Each model of course has major tech-
                             nological significance. The difference between the models becomes clear
                             when we consider what happens to a light wave when it has to have a
                             finite energy.


                             4.2.1 The Harmonic Electromagnetic Plane Wave
                             We can consider the harmonic electromagnetic plane wave in a vacuum
                             that satisfies Equation (4.10) as a basic component with which to build
                             up more detailed descriptions. Thus, following Equation (4.11), we select

                                                        (
                                                               •
                                            E =  E exp [  i – ωt –  kr)]          (4.41)
                                                  0
                             We first insert (4.41) into (4.1c), noting that ρ =  0  , to give
                                                       (
                                 ∇• E =  0 =  iE • exp [  i – ωt –  kr)]   or E •  k =  0  (4.42)
                                                              •
                                                k
                                              0
                                                                      0
                             We next use (4.1b), noting that, since σ =  0   that J =  0  , to obtain
                                       1
                                                     (
                                                           •
                                 H =  ----------k ×  E exp [  i – ωt –  kr)]   or H =  k ×  E 0  (4.43)
                                                                    0
                                              0
                                      ωµ
                                         0
                                                  k
                             We see that  E  ,  H   and   are cyclically perpendicular to each other.
                                         0   0
                                                           B
                                                                 E
                             Thus the mutually orthogonal vectors   and   always lie in a plane per-
                             pendicular to the direction of propagation  . Without sacrificing general-
                                                              k
                             ity for the plane wave case, we can assume now that the wave propagates
                             along the  -axis, the  E  -field lies parallel to the  -axis and the  B  -field
                                                                     y
                                     x
                             lies parallel to the  -axis, hence
                                            z
                                 E =   E cos ( ωt –  kx)  B =  B cos ( ωt –  kx –  α)
                                        0
                                                          z
                                                               0
                                   y
                                                                                  (4.44)
                                     E =  E =  0             B =  B =  0
                                           z
                                                               x
                                      x
                                                                    z
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