Page 53 - Shigley's Mechanical Engineering Design

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Mechanical Engineering Design
28
28 Mechanical Engineering Design
Use this result to determine the bilateral tolerance on the volume of a rectangular parallelepiped
with dimensions
a = 1.500 ± 0.002 in b = 1.875 ± 0.003 in c = 3.000 ± 0.004 in
1–16 A pivot in a linkage has a pin in the figure whose dimension a ± t a is to be established. The
thickness of the link clevis is 1.500 ± 0.005 in. The designer has concluded that a gap of between
0.004 and 0.05 in will satisfactorily sustain the function of the linkage pivot. Determine the
dimension a and its tolerance.

Clevis
Pin Snap ring
Problem 1–16
Dimensions in inches.

a ± t a 0.042 ± 0.002
1.500 ± 0.005

1–17 A circular cross section O ring has the dimensions shown in the figure. In particular, an AS 568A
standard No. 240 O ring has an inside diameter D i and a cross-section diameter d of
= 3.734 ± 0.028 in d = 0.139 ± 0.004 in
D i
¯
Estimate the mean outside diameter D o and its bilateral tolerance.

D i d

Problem 1–17

D 0

1–18 to For the table given, repeat Prob. 1–17 for the following O rings, given the AS 568A standard
1–21 number. Solve Problems 1–18 and 1–19 using SI units. Solve Problems 1–20 and 1–21 using ips
units. Note: The solutions require research.

Problem number 1–18 1–19 1–20 1–21
AS 568A No. 110 220 160 320

1–22 Convert the following to appropriate ips units:
(a) A stress, σ = 150 MPa.
(b) A force, F = 2 kN.
(c) A moment, M = 150 N m.
2
(d) An area, A = 1 500 mm .
4
(e) A second moment of area, I = 750 cm .
( f ) A modulus of elasticity, E = 145 GPa.
(g) A speed, v = 75 km/h.
(h) A volume, V = 1 liter.