Page 444 - Six Sigma Demystified
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424        Six SigMa  DemystifieD


                       60.	 	When	using	process	capability	estimates,
                           A.	the	process	must	be	in	control,	or	the	estimate	is	misleading.
                           b.	always	estimate	the	process	using	sample	sigma.
                           c.	we	should	sort	the	data	prior	to	analysis.
                           d.	All	the	above	are	true.
                       61.	 	A	90%	confidence	interval	for	the	mean	is	from	13.8067	to	18.1933.	This	means	that
                           A.	there	is	a	90	percent	probability	that	the	true	mean	lies	between	13.8067	and
                             18.1933.
                           b.	90	percent	of	all	values	in	the	population	lie	between	13.8067	and	18.1933.
                           c.	90	percent	of	all	the	sample	values	in	the	population	lie	between	13.8067	and
                             18.1933.
                           d.	All	the	above	are	true.
                       62.	 	Assuming	normality,	the	two-sided	95%	confidence	interval	on	the	mean	for	a
                           sample	of	20	units	with	an	average	of	121	and	a	standard	deviation	of	15	is
                           A.	(112.8,	129.2).
                           b.	(114.0,	128.0).
                           c.	(115.2,	126.8).
                           d.	(114.4,	127.6).

                       63.	 	Assuming	normality,	the	one-sided	upper	95%	confidence	interval	on	the	mean
                           for	a	sample	of	20	units	with	an	average	of	121	and	a	standard	deviation	of	15	is
                           A.	129.2.
                           b.	128.0.
                           c.	126.8.
                           d.	127.6.

                       64.	 	For	a	sample	of	20	units	with	an	average	of	121	and	a	standard	deviation	of	15,	a	two-
                           sided	hypothesis	that	the	mean	equals	115	(assuming	normality)	yields	a	result	of
                           A.	reject	the	null	hypothesis	that	the	mean	equals	115	because	the	p	value	is	less
                             than	0.05.
                           b.	reject	the	null	hypothesis	that	the	mean	equals	115	because	the	p	value	is	greater
                             than	0.05.
                           c.	assert	that	the	mean	equals	115	because	the	p	value	is	greater	than	0.05.
                           d.	The	mean	may	or	may	not	equal	115;	we	cannot	reject	the	hypothesis	that	the
                             mean	equals	115	because	the	p	value	is	greater	than	0.05.
                       65.	 	For	a	sample	of	20	units	with	an	average	of	121	and	a	standard	deviation	of	15,
                           for	an	alternative	one-sided	hypothesis	that	the	mean	is	greater	than	115
                           (assuming	normality),	we	should
                           A.	reject	the	null	hypothesis	that	the	mean	is	less	than	or	equal	to	115	and	assert	it
                             is	greater	than	115	because	the	p	value	is	less	than	0.05.
                           b.	reject	the	null	hypothesis	that	the	mean	is	less	than	or	equal	to	115	and	assert
                             that	it	is	greater	than	115	because	the	p	value	is	greater	than	0.05.
                           c.	reject	the	null	hypothesis	that	the	mean	is	greater	than	or	equal	to	115	and	assert
                             that	it	is	less	than	115	because	the	p	value	is	greater	than	0.05.
                           d.	The	mean	may	or	may	not	be	greater	than	115;	we	cannot	reject	the	hypothesis
                             that	the	mean	is	less	than	or	equal	to	115	because	the	p	value	is	greater	than	0.05.
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