Page 40 - Soil and water contamination, 2nd edition
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Basic environmental chemistry                                          27

                   where M = the total number of moles of compound i in the system and V  = the volume of
                          i                                                   j
                           3
                   phase  j [L ]. By combining the ideal gas law  (Equation 2.15) and Equation (2.24) with m  =
                                                                                         i,j
                   n /V, it can be shown that:
                    i
                             1
                    Z                                                                  (2.26)
                     air
                            R  T
                   where Z  = the fugacity  capacity constant for air. The fugacity capacity constant for other
                          air
                   phases depends on the compound’s partition coefficient  between that phase  and water and
                   the compound’s Henry’s law  constant . The fugacity capacity constant for water is:
                              1
                   Z
                     water                                                             (2.27)
                             K
                               H
                                                                                       2
                                                                                         -2
                   where Z   = the fugacity  capacity constant for water, K  = the Henry’s law  constant  [L  T ].
                          water                                H
                   For sediment , the fugacity capacity constant is:
                               K
                   Z          s  d
                     sed                                                               (2.28)
                             K
                               H
                   where Z  = the fugacity  capacity constant for sediment , ρ  = the bulk density  of sediment [M
                                                                s
                          sed
                    -3
                                                     3
                                                        -1
                   L ] and K  = the distribution coefficient  [L  M ] (see Equation 2.12). The number of moles
                           d
                   of the compound in each phase  can then be calculated by:
                   M        Z   f  V                                                   (2.29)
                     i, j    i,  j  i  j
                   For further details about the fugacity  concept, see Mackay (1991) or Schwarzenbach et al.
                   (1993).
                      Example 2.5  Fugacity
                                                                 3
                                                                                3
                      Consider a pond ecosystem  comprising 10 000 000 m  of air, 50 000 m  of water, and
                      400 m  of bottom sediment . Ten litres of the organic liquid benzene  is spilled into it.
                           3
                      Calculate the equilibrium partitioning  among air, water, and sediment using the fugacity
                      approach. Relevant data is given in the table below.
                      Benzene properties
                      Vapour pressure             0.125 atm
                                                            3
                      Henry’s law  constant    5.55·10 -3  atm · m  mol -1
                        Molecular weight          78.11 g mol -1
                      Specific density           873.81 kg m -3
                      Sediment properties
                      Bulk density                1100 kg m -3
                      Distribution coefficient for benzene   0.6 l kg -1
                      Solution
                      First, calculate the total amount of benzene  released expressed in moles:
                                              -1
                                   -1
                      10 l × 873.81 g l /78.11 g mol  = 112 mol

                      Second, calculate the fugacity  capacity for the three phases considered. For the air phase ,
                      use Equation (2.26):
                               1             1                       -1  -3
                      Z                                   40  9 .  mol atm  m
                        air                   4
                               RT      . 8  21  10  298 . 15






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        Soil and Water.indd   39                                                            10/1/2013   6:44:12 PM
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