Page 26 - Standard Handbook Of Petroleum & Natural Gas Engineering

Geometry 15

volume = 1/3 altitude area of base = 1/6 hran
lateral area = 1/2 slant height perimeter of base = 1/2 san
where r = radius of inscribed circle
a = side (of regular polygon)
n = number of sides
s = JTTi7

(vertex of pyramid directly above center of base)

Right circular cone
volume = 1/3 zr2h
lateral area = zrs
where r = radius of base
h = altitude
s = slant height = d m

Any pyramid or cone
volume = 1/3 Bh
where B = area of base
h = perpendicular distance from vertex to plane in which base lies
Wedge (Figure 1-20)

a.

(Rectangular base; a, parallel to a,a and at distance h above base)
volume = 1/6 hb(2a + a,)
Sphere
volume = V = 4/3 zrJ = 4.188790r5 = 1/6 zd3 = 0.523599d’
area = A = 4zr2 = nd2
where r = radius
d = 2r = diameter = = 1.240706 = = 0.56419fi