Page 300 - Structural Steel Designers Handbook AISC, AASHTO, AISI, ASTM, and ASCE-07 Design Standards
P. 300

Brockenbrough_Ch06.qxd  9/29/05  5:15 PM  Page 6.22



                                                 DESIGN OF BUILDING MEMBERS


                   6.22  CHAPTER SIX

                               5. PNA at the bottom of the top flange (∆A f = A f ).

                                         ∑ Q = 324 5 2  .  ×   =
                                                  .
                                                   − ×1 675 50 157 0 .  kips
                                            n
                                            a =   157 0 .  = 0 68410 in
                                                             .
                                                       ×
                                                     .
                                                .
                                               085  × 30 90
                                                              =
                                            e =  13 7 .  + 5 25 0 6841 11 758 in
                                                     .
                                                                 .
                                                        − .
                                                2
                                                                        
                                                                  −
                                                                 .
                                                                      . )
                                                      .
                                                          + . (
                                                                             − .
                                                                           .
                                           M = 157 0 .  ×11 758 0 5 324 5 157 0 13 7 0 335 2 324 5 . .  −157 0 .   
                                                                        
                                                                                         ×
                                            n
                                                                                   ×1 675 50
                                                      ⋅
                                              = 2965 kip in
                                              =
                                          ϕ M = 0 90 2965 222 4.  ×  =  .  kip ⋅ft
                                            n
                               6. Plastic neutral axis within the web: ∑Q n = 104 kips is the average of items 5 and 7. (See Table 6.3.):
                                         ∑ Q =  157 0 .  + 81 1 .  = 119 1 .  kips
                                            n
                                                   2
                                            a =   119 1 .  = 0 5187 in
                                                            .
                                                      ×
                                                     .
                                                .
                                               085 × 30 90
                                            e =  13 7 .  + 5 25 0 5187 11 841 in
                                                              =
                                                     .
                                                       − .
                                                                 .
                                                2
                                                                                  324 5 .  −119 1 .  
                                                                   −
                                                                             − .
                                                                           .
                                                                       . )
                                                          + . (
                                                                 .
                                                      .
                                           M = 119 1 .  ×11 5187 0 5 324 5 119 1 13 7 0 335  2  ×1 675 50 
                                                                         
                                            n
                                                                                         ×
                                                                                      .
                                                     ⋅
                                             = 2775 kip in
                                          ϕ M = 0.90 2775 208 1×  =  .  kip ⋅ft
                                                90
                                            n
                                         ∑ Q =        ×     =
                               7.            n  C = 025 3245 811 .  kips
                                                          .
                                                    .
                                                c
                                            a =    81 1 .  = 0 3535 in
                                                             .
                                                       ×
                                               085 × 30 90
                                                .
                                                     .
                                                    .
                                    C c  ( d − 2 )  =  81 1
                                           t
                                   2 P yw   f  2  × 0 23 50.  ×
                                              = 353.   in  = distance from PNA to the center of gravity of the beam
                                                                                            335
                                                .
                                             y =  0 335 × 5 0.  × 13 7 2 3 53 0 335 2( . /  + .  − .  / ) + 0 23 13 7 2 3 53 0. [( . /  + .  − .335 2)/ ] 2
                                                                  +
                                                                                  −
                                                              ×
                                                          0335 50 023 137 2) + 353 0335]
                                                                .
                                                                                    .
                                                           .
                                                                      [
                                                                               .
                                                                         .
                                                                       (
                                                                           /
                                                                    .
                                              =  720 in  = distance from centroid tensile portion of beam to the
                                                .
                                               center of gravity of the beam
                                                 .
                                                                    .
                                                        +
                                                            +
                                                               .
                                                          .
                                                     .
                                             e  =  13 7  −  353 720 525−  0 3535
                                                2                    2
                                                 .
                                             e  = 15 60 in  = distance from PNA to C c
                                                                    .
                                                            +
                                                        +
                                            y ′ =  13 7 .  −  353 720 525−  0 335
                                                     .
                                                               .
                                                          .
                                                2                   2
                                                 .
                                                                       C
                                            y ′ = 10 36 in  = distance from PNA to C flange
                           Downloaded from Digital Engineering Library @ McGraw-Hill (www.digitalengineeringlibrary.com)
                                      Copyright © 2004 The McGraw-Hill Companies. All rights reserved.
                                       Any use is subject to the Terms of Use as given at the website.
   295   296   297   298   299   300   301   302   303   304   305