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Brockenbrough_Ch06.qxd  9/29/05  5:15 PM  Page 6.26



                                                 DESIGN OF BUILDING MEMBERS


                   6.26  CHAPTER SIX

                               The effective supported weight of joist, beam, or girder is
                                                                W = wBL                            (6.33)

                               where w = supported weight per unit area
                                    B = effective width
                                    L = member span
                                 For the vibration analysis, additional parameters pertaining to the entire floor system must be
                               established first for the best estimation of peak accelerations due to a heel-drop forcing function.
                               The entire floor dimensions are 180 ft × 90 ft. The girders on all four sides are W24 × 55 Grade 50. The
                               interior girders are also W24 × 55 Grade 50 sections spaced at 30 ft in the longitudinal and latitudi-
                               nal directions.
                                 The loading must be adjusted to estimate the least loading scenario which is most critical to
                                                                2
                               extreme vibrations. A dead load of 46.7 lb/ft is estimated by considering 3.5 in of concrete, 1-in
                                                                              2
                                                              2
                               effective concrete thickness of deck, 2 lb/ft metal deck, and 4 lb/ft for ceiling, mechanical, and min-
                                                                                  2
                               imal partition loads. The live load is reduced to a magnitude of 11 lb/ft .
                                 For transformed composite moment of inertia calculations, there are two modifications that dif-
                               fer from traditional composite calculations. First, a dynamic modulus of elasticity is considered
                               because the stiffness of concrete is greater under a dynamic load as compared to a static load. The
                               dynamic modular ratio is defined as
                                                              n =   E s                            (6.34)
                                                                  .
                                                                 135  ×  E s
                               For this example,
                                                                 ,
                                                           n =  29 000  = 10 06
                                                                         .
                                                             1 35 × 2136
                                                              .
                                 The effective width of the slab is the minimum of the member spacing or 0.4 × (member span)
                               for an interior member and 0.20 × (member span) for an exterior member. The concrete flange width
                               is the smaller of b = 10 × 12 = 120 in or b = 0.4 × 30 × 12 = 144 in.
                               Interior Beam Vibration Investigation.  The beam vibration calculations will be based on full com-
                               posite action, and the shear deformations will not be included.
                                 The concrete flange width is the smaller of b = 120 in or b = 144 in. The transformed moment of
                                             4
                               inertia I t = 843.2 in for the W14 × 22 beam, not considering the 1-in effective concrete in the deck.
                                 The total load is
                                                      (46.7 + 11.0) × 10 + 22 = 0.6 kip/ft
                               and the beam deflection is calculated as

                                                            × 6 30
                                                      ∆ =  50.  ×  4  ×12 3  = 0 447 in
                                                                            .
                                                       j
                                                                   ×
                                                                ,
                                                          384  × 29 000 843 2 .
                                                               386
                                                                     .
                                                          .
                                                      f = 018      = 529 Hz
                                                       n
                                                              0 447
                                                               .
                               The effective width of a joist or beam is
                                                                /
                                                             D   14  2
                                                      B =  C j  s    L <  ×  floor width         (6.35)
                                                             D   j  3
                                                       j
                                                              j
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