Page 306 - Structural Steel Designers Handbook AISC, AASHTO, AISI, ASTM, and ASCE-07 Design Standards
P. 306

Brockenbrough_Ch06.qxd  9/29/05  5:15 PM  Page 6.28



                                                 DESIGN OF BUILDING MEMBERS


                   6.28  CHAPTER SIX

                               where C g = 1.6 for girders supporting joists connected to the girder flange (e.g., joist seats)
                                      = 1.8 for girders supporting beams connected to the girder web
                                    D g = girder transformed slab moment of inertia per unit width
                                         3
                                               4
                                      = d e /12n, in /ft
                                    D j = beam or joist transformed moment of inertia per unit width
                                             4
                                      = I g /S, in /ft
                                    L g = girder span
                                                        D =  4315 ×12  = 143 85.   in /ft
                                                                            4
                                                         j
                                                              30
                               For this girder, C g = 1.8.
                                                             /
                                               B = 18  ×  84 32.    14  × 30  = 47 245 ft  <  2  × floor length
                                                                     .
                                                   .
                                                g
                                                       4315                3
                               The girders are not affected by continuous action.
                                                           .
                                                      W =  1 853  × 47 25 30.  ×  = 87 56.  kips
                                                       g
                                                           30
                               Combined Vibration Investigation.  The girder vibration calculations will be based on full com-
                               posite action and the shear deformations will not be included.
                                 For the combined mode, the equivalent weight is
                                                              ∆         ∆
                                                        W =    j  W +    g  W                      (6.37)
                                                            ∆  j  + ∆  g  j  ∆  j  + ∆  g  g

                               where ∆ j , ∆ g = beam, joist, or girder maximum deflection
                                 If the girder span L g is greater than the joist or beam effective width B j , then the following adjust-
                               ment to the girder deflection is applicable but L g /B j ≥ 0.5:
                                                                   L
                                                              ∆ ′ =  g  ∆ (  )                     (6.38)
                                                                g
                                                                   B j  g
                               Since L g /B j = 30/32.91 = 0.912 ≤ 1, then

                                             ∆ ′ =  30  (.  = 0 246 in
                                                             .
                                                      0 269)
                                              g
                                                 32 91
                                                   .
                                                                     .
                                                     .
                                                                                   .
                                                                             .
                                                             .
                                             W  =   0 447  88 76  +  0 246  87 56  = 88 327 kips
                                                                  .
                                                       .
                                                  .
                                                                       .
                                                 0 447 + 0 246   0 447  + 0 246
                               The combined natural frequency is calculated as follows:
                                                                  386
                                                           .
                                                     f comb  = 018       = 4 249.  Hz
                                                                .
                                                               0 447 + 0 246.
                                 For a typical modular office with small demountable partitions, β= 0.03 and P o = 65 lb.
                                             a p  =  65 × exp( −0 35 4 249)  ×100%  = 0 55%  > 0 5 . %  NG
                                                            × .
                                                         .
                                                                          .
                                             g    0 03 × 88 327 ×1000
                                                   .
                                                        .
                           Downloaded from Digital Engineering Library @ McGraw-Hill (www.digitalengineeringlibrary.com)
                                      Copyright © 2004 The McGraw-Hill Companies. All rights reserved.
                                       Any use is subject to the Terms of Use as given at the website.
   301   302   303   304   305   306   307   308   309   310   311