Page 65 - The engineering of chemical reactions
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Variable Density 49
                                 To solve the batch-reactor mass-balance equation, we write

                                               CA   =  $!  =  NAo(l   -  x)  =  cAo 1  -  x
                                                          V0(1 +2x)       1 + 2 x
                            so that we have written CA  as a function of X and constants.
                                For this problem the equation dCA/dt =  -WA  is not appropriate, and we must solve
                            the equation
                                              dNA          = v,(l  + 2X)kC,4,  1 - x
                                              -  = -vkCA
                                              dt                           1+2x
                            Since  dNA  ‘=  -NAP  dX,   this mass-balance equation on species A  can be converted to
                                               dx
                                               -  =  +p  -  X)(1   +2x)  =  k(l   _  x)
                                                dt          1 + 2 x
                            This equation can be separated to yield
                                                           dX
                                                          - = k d t
                                                          1 - x
                            and integrated from X = 0 at t  = 0 to give
                                                        X
                                                          dX    1   ’   dX
                                                   t=     -=-         -
                                                       s r(X)    k s 1 - x
                                                      x=0         x=0

                                                    =  --i   ln(1  -  X)
                            This equation can be solved for X(t),
                                                         X(t)   = 1  - e-kr
                            Finally, substituting back into  CA(X),  we obtain

                                                  1 - x          e-kt             ,-kt
                                       c , ( t )  =  CA‘,--   = CAo       -  CAo
                                                  1 + x      1 +  2(1  - e-kt) -  3 - 2eekt
                                Next consider the preceding as an  &h-order  irreversible reaction
                                                      A-+mB,      r=kC;
                            The mass balance is

                                                         dN.4
                                                         -   =  -VkC” A
                                                          dt
                            or
                                              dX
                                              -   = kC;,‘(l   -  X)“[l  +  (m  -  1)x]++’
                                               dt
                            and this equation can be separated to yield

                                                      1   x  [l  +  (m  -  l>X]n-l   dX
                                                t=-
                                                    kc;,’ s     (1 - x>n
                                                          0
                            This equation can be solved for t(X)  or  t  (CA)  by partial fractions, but the solution is not
                            pahcuhrly  simple to solve explicitly for X(t)  or  CA(r).
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