Page 61 - The engineering of chemical reactions
P. 61

The Batch Reactor  45

            Figure 2-7  Plots of CA versus t for an irreversible reaction for
            n = 0, i, and - 1. The kinetics for all reactions must approach first
            order as the reactant concentration approaches zero to be consistent
            with equilibrium requirements.









                                                                                                  I
                                                                                                  3

                                                                           C;;k(n-1)t



                                                        Njo  - Nj
                                                                 =  const
                                                           vj
                            or
                                                         Cjo-Cj   _
                                                                 - const
                            for a constant-density system. Therefore, for this reaction the loss in  A  is equal to the loss
                            in  B,  which is equal to f  the gain in C, or in symbols
                                                                     1
                                                CA   -  CAc,  =  CB   -  c&, =  -(CC,   - CC)
                                                                     3
                            Therefore, we can immediately solve for the concentration of  B,

                                                       CB  =  CBo   -  CAo  +  CA
                            Substitution of  CB  in terms of  CA  yields
                                                          dC.4
                                                                      =  - k d t
                                                    CA(CBo   -  CAo  +  CA>
                            If  CAM  =  CnO  at t  = 0, then  CA  =  CB  at all times, and this expression is identical to the
                            expression for a second-order reaction
                                                          dCA = -kc2
                                                           dt        A
                            This equation can be integrated to yield

                                                                  CA0
                                                        CA(t)  =
                                                                1  +  CA&t
                             and we can  find  Ce  (t)  =  CA(t)   and  Cc(t)  by substitution of  CA(~)   into the preceding
                             relations.
                                 We could also solve this equation in terms of the fractional conversion X by expressing
                             both  CA  and Cn  in terms of X. We can write CA  = CA,,(  1 -  X), which gives  dCA  =
                             -CAM  dX.   If  CA,,  =  Cs,,,  then the mass balance becomes
   56   57   58   59   60   61   62   63   64   65   66