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0066_frame_C14.fm  Page 15  Wednesday, January 9, 2002  1:49 PM









                       where x is the displacement of a translational microstructure (plunger), m is the mass of a movable
                       plunger, B v  is the viscous friction coefficient, k s1  and k s2  are the spring constants (the spring can be made
                                                                                               ∂W c i, x)
                                                                                                  (
                       from polysilicon), and F e (t) is the magnetic force which is found using the coenergy W c , F e (i, x) = ----------------------- .
                                                                                                 ∂x
                         The stretch and restoring forces are not directly proportional to the displacement, and these forces
                       are different on either side of the equilibrium position. The restoring/stretching force exerted by the
                                                         2
                       polysilicon spring is expressed as (k s1 x + k s2 x ).
                         Assuming that the magnetic system is linear, the coenergy is expressed as

                                                         (
                                                      W c i, x) =  1  2
                                                                --Lx()i
                                                                2
                       Then

                                                      F e i, x(  ) =  1 2dL x()
                                                               --i --------------
                                                               2   dx

                         The inductance is found as

                                                                   2
                                                        2
                                                      N
                                             Lx() =  ------------------ =  --------------------------------------------------
                                                                 N µ f µ 0 A f A g
                                                    ℜ f +  ℜ g  A g l f + 2A f µ f x + 2d)
                                                                        (
                       where ℜ f  and ℜ g  are the reluctances of the ferromagnetic material and air gap, A f  and A g  are  the associated
                       cross section areas, and l f  and (x + 2d) are the lengths of the magnetic material and the air gap.
                       Hence
                                                              2  2  2
                                                 dL    – ---------------------------------------------------------
                                                 ------ =
                                                            2N m f m 0 A f A g
                                                                   (
                                                 dx     [ A g l f +  2A f µ f x + 2d)] 2
                         Using Kirchhoff’s law, the voltage equation for the phase microcircuitry is
                                                                 dψ
                                                         u a =  ri +  -------
                                                                 dt

                       where the flux linkage ψ is expressed as ψ = L(x)i.
                         One obtains

                                                              di
                                                                   dL x()dx
                                                   u a =  ri + L x()----- +  i--------------------
                                                              dt    dx dt
                       and thus

                                                             2  2  2
                                        di     r          2N µ f µ 0 A f A g     1
                                        ----- =  –  -----------i +  --------------------------------------------------------------------iv +  -----------u a
                                                                   (
                                                        [
                                        dt    Lx()  Lx() A g l f + 2A f µ f x +  2d)] 2  Lx()
                         Augmenting this equation with differential equation
                                                     2
                                                    d x
                                            Ft() =  m-------- +  B v dx  ( k s1 x +  k s2 x ) + F e t()
                                                           ------ +
                                                                         2
                                                     dt 2  dt
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