Page 108 - INTRODUCTION TO THE CALCULUS OF VARIATIONS
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Euler-Lagrange equations                                           95

                Applying Lebesgue dominated convergence theorem we deduce that (3.7) holds.
                   Step 3 (Derivation of (E w ) and (E)). The conclusion of the theorem follows
                from the preceding step. Indeed since u is a minimizer of (P) then
                                                            1,p
                                   I (u +  ϕ) ≥ I (u) , ∀ϕ ∈ W  (Ω)
                                                           0
                and thus
                                          I (u +  ϕ) − I (u)
                                       lim                =0
                                        →0
                which combined with (3.7) implies (E w ).
                   To get (E) it remains to integrate by parts (using Exercise 1.4.7) and to find
                          Z
                                                                         1,p
                     (E w )  [f u (x, u, ∇u) − div f ξ (x, u, ∇u)] ϕdx =0, ∀ϕ ∈ W  (Ω) .
                                                                         0
                           Ω
                The fundamental lemma of the calculus of variations (Theorem 1.24) implies the
                claim.
                   Step 4 (Converse). Let u be a solution of (E w ) (note that any solution of
                (E) is necessarily a solution of (E w )). From the convexity of f we deduce that
                                  1,p
                for every u ∈ u 0 + W 0  (Ω) the following holds
                           f (x, u, ∇u) ≥ f (x, u, ∇u)+ f u (x, u, ∇u)(u − u)
                                           + hf ξ (x, u, ∇u);(∇u −∇u)i .
                                                              1,p
                Integrating, using (E w )and the factthat u − u ∈ W  (Ω) we immediately get
                                                             0
                that I (u) ≥ I (u) and hence the theorem.
                   We now discuss some examples.
                Example 3.13 In the case of Dirichlet integral we have
                                                         1  2
                                       f (x, u, ξ)= f (ξ)=  |ξ|
                                                         2
                which satisfies (H3). The equation (E w )is then
                               Z
                                                                1,2
                                  h∇u (x); ∇ϕ (x)i dx =0, ∀ϕ ∈ W  (Ω)
                                                               0
                                 Ω
                while (E) is ∆u =0.
                Example 3.14 Consider the generalization of the preceding example, where
                                                        1   p
                                       f (x, u, ξ)= f (ξ)=  |ξ| .
                                                        p
                The equation (E) is known as the p-Laplace equation (so called, since when p =2
                it corresponds to Laplace equation)
                                         h          i
                                              p−2
                                      div |∇u|   ∇u =0,in Ω .
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