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164                                             Isoperimetric inequality

                       Remark 6.17 (i) The proof that we will give is also valid in the case n =2.
                       However it is unduly complicated and less precise than the one given in the
                       preceding section.
                          (ii) Concerning the uniqueness that we will not prove below (cf. Berger [10],
                       Section 12.11), we should point out that it is a uniqueness only among convex
                       sets. In dimension 2, we did not need this restriction; since for a non convex set
                       A, its convex hull has larger area and smaller perimeter. In higher dimensions
                       this is not true anymore. In the case n ≥ 3, one can still obtain uniqueness by
                       assuming some regularity of the boundary ∂A, in order to avoid "hairy" spheres
                       (i.e., sets that have zero n and (n − 1) measures but non zero lower dimensional
                       measures).

                                                         n
                          Proof. (Theorem 6.16). Let A ⊂ R be compact, we have from the definition
                       of L (see Minkowski-Steiner formula) and from Theorem 6.13 that

                                                  ¡      ¢
                                               M A + B   − M (A)
                              L (∂A) = lim inf
                                            →0
                                               ⎡ h       1/n          1/n i n      ⎤
                                                  (M (A))   +(M (B   ))    − M (A)
                                      ≥ lim inf  ⎣                                 ⎦  .
                                            →0
                                      n
                       Since M (B ε )=   ω n ,weget
                                                           ∙              ¸ n
                                                                ³     ´ 1/n
                                                            1+     ω n       − 1
                                                                  M(A)
                                   L (∂A) ≥ M (A) lim inf
                                                       →0
                                                       µ       ¶ 1/n
                                                           ω n
                                           = M (A) · n
                                                         M (A)
                       and the isoperimetric inequality follows.
                          We conclude the present section with an idea of the proof of Brunn-Minkowski
                       theorem (for more details see Berger [10], Section 11.8.8, Federer [45], page 277
                       or Webster [96] Theorem 6.5.7). In Exercise 6.3.1 we will propose a proof of the
                                                                                    n
                       theorem valid in the case n =1. Still another proof in the case of R can be
                       found in Pisier [84].
                          Proof. (Theorem 6.13). The proof is divided into four steps.
                          Step 1. We first prove an elementary inequality. Let u i > 0, λ i ≥ 0 with
                        i=1 i =1,then
                       Σ n  λ
                                                  n        n
                                                  Y       X
                                                    u λ i  ≤  λ i u i .                 (6.1)
                                                      i
                                                  i=1     i=1
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