Page 35 - INTRODUCTION TO THE CALCULUS OF VARIATIONS
P. 35

22                                                        Preliminaries

                       Using Hölder inequality, (1.1) and (1.3) for the first term in the right hand side
                       of the inequality, we obtain
                                                                      ¯              ¯
                          ¯Z              ¯
                            1                                         ¯ Z  a i       ¯
                          ¯               ¯                      I P  ¯              ¯
                          ¯   u ν (x) ϕ (x) dx ≤ ku ν k L p kϕ − hk L p 0 +  |α i | ¯  u ν (x) dx¯
                                          ¯
                          ¯               ¯
                            0                                   i=1   ¯  a i−1       ¯
                                                                                        (1.4)
                                                        ¯             ¯
                                                         Z
                                                   I    ¯  a i        ¯
                                                  P     ¯             ¯
                                       ≤   kuk L p +  |α i | ¯  u ν (x) dx¯ .
                                                  i=1   ¯  a i−1      ¯
                       To conclude we still have to evaluate
                           Z                 Z                Z
                             a i               a i           1  νa i
                               u ν (x) dx =       u (νx) dx =       u (y) dy
                                                             ν
                            a i−1             a i−1             νa i−1
                                               (                                       )
                                                Z  [νa i−1 ]+1  Z  [νa i ]     Z  νa i
                                             1
                                         =                udy +          udy +     udy
                                             ν                   [νa i−1 ]+1    [νa i ]
                                                  νa i−1
                       where [a] stands for the integer part of a ≥ 0. Wenow usethe periodicityof
                       u in the second term, this is legal since [νa i ] − ([νa i−1 ]+1) is an integer, we
                       therefore find that
                              ¯            ¯
                               Z                 Z  1                       ¯Z  1  ¯
                              ¯  a i       ¯   2                                   ¯
                              ¯            ¯                [νa i ] − [νa i−1 − 1] ¯
                                   u ν (x) dx¯ ≤    |u| dy +                ¯   udy .
                                                                                   ¯
                              ¯                                             ¯      ¯
                              ¯            ¯   ν  0                ν          0
                                a i−1
                                R  1
                       Since u =   u =0, we have, using the above inequality, and returning to (1.4)
                                 0
                                       ¯Z  1     ¯                    I
                                       ¯         ¯           2      X
                                       ¯         ¯        p +           |α i | .
                                           u ν ϕdx ≤   kuk     kuk  1
                                       ¯         ¯       L   ν    L
                                         0
                                                                     i=1
                       Let ν →∞, we hence obtain
                                                       1
                                                    ¯Z        ¯
                                                    ¯         ¯
                                          0 ≤ lim sup  ¯  u ν ϕdx ≤   kuk L p .
                                                              ¯
                                                    ¯         ¯
                                               ν→∞    0
                       Since   is arbitrary, we immediately have (1.2) and thus the result.
                          We conclude the present Section with a result that will be used on several
                       occasions when deriving the Euler-Lagrange equation associated to the problems
                       of the calculus of variations. We start with a definition.
                                                 n
                       Definition 1.23 Let Ω ⊂ R be an open set and 1 ≤ p ≤∞. We say that
                            p            p
                                                                 0
                                             0
                       u ∈ L  (Ω) if u ∈ L (Ω ) for every open set Ω compactly contained in Ω (i.e.
                            loc
                       Ω ⊂ Ω and Ω is compact).
                                   0
                        0
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