Page 209 - Thomson, William Tyrrell-Theory of Vibration with Applications-Taylor _ Francis (2010)
P. 209

196                              Properties of Vibrating Systems   Chap. 6

                                  Any of the modes corresponding to   must be orthogonal to   if it is to be
                              a  normal  mode.  If all  three  modes  are  orthogonal,  they  are  linearly  independent
                              and  can  be  combined  to  describe  the  free  vibration  resulting  from  any  initial
                              condition.
                                  The eigenvectors associated with the equal eigenvalues are orthogonal to the
                              remaining eigenvectors, but  they may not be orthogonal to each  other.
                              Example 6.11-1
                                  Consider  the  system  of  Fig.  6.11-1  of a  flexible  beam  with  three  lumped  masses.  Of
                                  the  three  possible  modes  shown,  the  first  two  represent  rigid  body  motion  of
                                  translation  and  rotation  corresponding to  zero  frequency,  and  the  third  mode  is  that
                                  of symmetric vibration  of the  flexible  beam.  With  the  mass  matrix equal  to

                                                                1 0  0
                                                           M =  0   2   0
                                                               0   0   1
                                  the  modes  are  easily  shown  to be orthogonal  to each  other,  i.e.,



                                       Next,  multiply (¡>2  by a constant  h  and  add  it to  (/>,  to form a new modal vector
                                  ^12*
                                                                             1  -  b
                                                               M            1
                                                                               1
                                                               u    1   i /    \  1  + h
                                                               i.e.,
                                                                   1    0   0   1-6^

                                                      (-1    1    -1) 0   2   0  1    } ==0
                                                                  0  0  1   \  + h\
                                  Thus, the new eigenvector formed by a linear combination of (/)j  and </>2  is orthogonal

                                            I
                        O           ■o— .....    o
                        m           Z m          m


                                                             x^ = o
                        o_------------------ -O'-*






                        ck       ___
                         \     ^ ----
                                                               3E/
                                                    +3=   1    X=
                                   ‘O - - -                          Figure  6.11-1.
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