Page 211 - Thomson, William Tyrrell-Theory of Vibration with Applications-Taylor _ Francis (2010)
P. 211
198 Properties of Vibrating Systems Chap. 6
¡ 1 'c • ~ ~T ' 1 ’
(a)
Thus, the roots or the eigenvalues for the system are
Ai = 0
A2 = 1
To identify the corresponding eigenvectors, each of the A’s is substituted into
the equation of motion:
(1-A ) - 1 0
0 (2 -A ) -1
0 -1 (1-A )
When Aj = 0 is substituted, the result is = ^2 ^ ^3 normal mode, or
eigenvector, is
*, = |!
which describes the rigid body motion [see Fig. 6.12-2(a)].
Similarly, the second and third modes [see Figs. 6.12-2(b) and 6.12-2(c), respec
tively] are found and displayed as
n ( 1
(t>2 '■= 0 <^3 = - 2
1 1
P R O B LEM S
6-1 Determine the flexibility matrix for the spring-mass system shown in Fig. P6-1.
«1 3 ^
V7777777//, Figure P6-1.