Page 33 - Thomson, William Tyrrell-Theory of Vibration with Applications-Taylor _ Francis (2010)
P. 33

20                                             Free Vibration   Chap. 2

                                  The  statical  deflection  of the  spring  suspending  the  ^-kg  mass  is  obtained  from  the
                                  relationship  mg  = kA
                                                       mg    0.25  X  9.81
                                                                         16.0 mm
                                                               0.1533

                                                      ^N /m m
                             Example 2.2-2
                                  Determine  the  natural  frequency  of the  mass  M  on  the  end  of a  cantilever beam  of
                                  negligible mass shown  in  Fig. 2.2-2.
                                                            M
                                           I              n -
                                                     2
                                                              _1_   Figure 2.2-2.
                             Solution:  The deflection of the cantilever beam under a concentrated end force  P  is
                                                               pp   p
                                                           ^   3EI   k
                                  where  El  is  the  flexural  rigidity.  Thus,  the  stiffness of the  beam  is  k = 3EI/P,  and
                                  the natural frequency of the  system becomes
                                                              J _   / 3 ^
                                                           '
                                                          ■''   2-17 V mP

                             Example 2.2-3
                                  An  automobile wheel  and tire  are suspended by a steel  rod 0.50 cm in  diameter and
                                  2  m  long,  as  shown  in  Fig.  2.2-3.  When  the  wheel  is  given  an  angular  displacement
                                  and  released,  it  makes  10  oscillations  in  30.2  s.  Determine  the  polar  moment  of
                                  inertia of the wheel and  tire.
                             Solution:  The rotational equation of motion corresponding to Newton’s equation is
                                                            Je  =  -K6
                                  where  J  is the rotational mass moment of inertia,  K  is the rotational stiffness,  and  6
                                  is the  angle of rotation  in  radians. Thus,  the  natural frequency of oscillation  is equal














                                                                     Figure 2.2-3.
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