Page 31 - Thomson, William Tyrrell-Theory of Vibration with Applications-Taylor _ Francis (2010)
P. 31

18                                            Free Vibration   Chap. 2

                       2.2  EQUATIONS OF MOTION:  NATURAL FREQUENCY
                              Figure  2.2-1  shows  a  simple  undamped  spring-mass  system,  which  is  assumed  to
                              move only along the vertical direction.  It has 1  degree of freedom (DOF), because
                              its motion is described by a single coordinate  x.
                                  When placed into motion, oscillation will take place at the natural frequency
                              /„, which is a property of the system. We now examine some of the basic concepts
                              associated with the free vibration of systems with  1  degree of freedom.
                                  Newton’s second law is the first basis for examining the motion of the system.
                              As  shown  in  Fig.  2.2-1  the  deformation  of  the  spring  in  the  static  equilibrium
                              position is  A,  and the spring force  A:A  is equal to the gravitational force  w  acting
                              on mass  m:
                                                         A:A «F vv  = mg                  (2.2-1)
                              By measuring the  displacement  x  from the  static  equilibrium position,  the  forces
                              acting on  m  are  k(A  + x) and  w.  With  x  chosen to be positive in the  downward
                              direction, all quantities—force, velocity, and acceleration—are also positive in the
                              downward direction.
                                  We now apply Newton’s second law of motion  to the mass  m:
                                                    mx  =  XF = w  -  k(A  + jc)

                              and because  kA  = w, we obtain
                                                          mx =  -k x                      (2.2-2)
                              It is evident that the choice of the static equilibrium position as reference for x  has
                              eliminated  w,  the  force  due  to  gravity,  and  the  static  spring  force  kA  from  the
                              equation of motion, and the resultant force on  m  is simply the spring force due to
                              the displacement  jc.
                                  By defining the circular frequency o)^  by the equation
                                                            2   ^                         (2.2-3)
                                                                m






                                                                     /f(A -^x)
                                                                           Static  equilibrium
                                                                              posifion

                                                                          IM'
                                          Figure 2.2-1.  Spring-mass system and free-body diagram.
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