Page 269 - Thermodynamics of Biochemical Reactions

Chemical Equilibrium in One Phase Systems 269

{I-2768.1, -3619.21, -4, 12}, {-2811.48, -3612.91, -3, 13}, I-2838.18, -3627.91, -2, 141

This program is run three times at I = 0, 0.10, and 0.25 M.

Tab1eFo~~ca1cdGTsptat~sp,~283.15,298.15,1eHeadings-
> { { "ATP-4 'I, "HATP-3" "H2ATP-2" 1, { "28 3.15 K" , "298.15 K" , "3 13.15 K" 1 } ]
I
283.15 K 298.15 K 313.15 K
ATP-4 -2810.92 -2768.1 -2725.28
HATP-3 -2851.8 -2811.48 -2771.16
H2ATP-2 -2877.91 -2838.18 -2798.45

Tab1eFormtca1cdGTs~tatpsp,(283.15,298.151eHead~ngs-
>{ { "ATP-4 " I "HATP- 3", "H2ATP-2" 1, E "2 83.15 K" , "298.15 K" , "313.15 K" 1 1 I

283.15 K 298.15 K 313.15 K
ATP-4 -2819.99 -2777.89 -2735.84
HATP-3 -2856.9 -2816.99 -2777.1
H2ATP-2 -2880.18 -2840.63 -2801.09

TableFormlcalcdGTsp[atps~,{283.15,298.15,313.15},.25],~TableHeadings-
> { { "ATP-4 'I, "HATP- 3 " , "H2ATP-2 " 1 , "2 83 -15 K" , "298.15 K" , "313.15 K" 1 } I
{
283.15 K 298.15 K 313.15 K
ATP- 4 -2822.92 -2781.06 -2739.25

HATP-3 -2858.55 -2818.77 -2779.02
H2ATP-2 -2880.91 -2841.42 -2801.94
3.7 Calculate the adjustments to be subtracted from pH, obtained with a pH meter to obtain pH,= -log[H' at 0 "C to 40 "C
and ionic strengths of 0,O. 10, and 0.25 M.

The values of o in the Debye-Huckel equation are given by

data={{273.15,1.12938),{283.15,1.14717},{293.15,1.16598},{298.15,1.17582~,~303.15,1.185
99),{313.15,1.20732)}

{{273.15, 1.12938}, {283.15, 1.14717}, (293.15, 1.16598}, {298.15, 1.175821,
{303.15, 1.18599}, {313.15, 1.20732))

TableForm[datal
273.15 1.12938
283.15 1.14717
293.15 1.16598
298.15 1.17582
303.15 1.18599
313.15 1.20732

alpha=Fit [data, (1, t, t "2 } , t]
-6 2
1.10708 - 0.00154508 t + 5.95584 10 t

alpha
-6 2
1.10708 - 0.00154508 t + 5.95584 10 t