Page 382 - Thermodynamics of Biochemical Reactions

382 Mathematica Solutions to Problems

Now calculate the further transformed Gibbs energies of formation of these reactants at the specified concentrations of ATP
and ADP

gppglucose6phos=gpglucose6phos-
(~pat~+8.31451*.29815*Log[.0001~)+(~adp+8.31451*.29815*Log~.011~

-449.906

gppfructose6phos=ggfructose6~hos-
(~atg+8.31451*.29815*Log[.0001])+(~adg+8.31451*.29815*Log~.~11~
-446.611

gpgfructose16phos=ggfructosel6ghose16phos-2*(g~at~+8.31451*.29815*Log[.00011)+2*~gpadp+8.31451
*.29815*Log[.O11)

-452.647
(b) Calculate the further transformed Gibbs energy of formation of the speudoisomer group

calciso CtransG-l : =
Module[{},(*This program produces the function of pH and ionic strength that gives
the standard transformed Gibbs energy of formation of a
pseudoisomer group at 298.15 K. The input is a list of the names of the functions for
the pseudoisomers in the groups. Energies are expressed in kJ molA-l.*)
-8.31451*.29815*
Log[Apply[Plus, ExpC-1*transG/(8.31451*.29815)11]1

gppiso=calc~so[~ggpglucose6phos,gpgfructctosel6phoS~~
-453.514

(c) Calculate the equilibrium mole fractions

r~=Exp[(g~~iso-{ggpg1ucose6phos,gppf~ctose6pho6,gppf~cto6e16phos})/(8.31451*.29815~1

{O .233262, 0.061748, 0.704991

(d) Now increase the ATP steady state concentration by a factor of 100

gppglucose6phos=gpglucose6phos-
(gpat~+8.31451*.29815*Log[.01l)+(ggadg+8.31451*.29815*Log~.011~
-461.322

gppfructose6phos=gpfructose6phos-
(ggatp+8.31451*.29815*Log[.Oll)+(gpadg+8.31451*.29815*Log[.Ol~
-458.027

gppfructose16phos=gpf~ctose16phos-2*(ggatp+8.31451*.29815*Log1.011~+2*~~~ad~+8.31~~1*.
29815*Log I. 011 1
-475.48

-475.49