Page 383 - Thermodynamics of Biochemical Reactions
P. 383

Use of Semigrand Partition Functions   383



               ri=Exp[(g~piso-{gppg1ucose6~hos,~pfructose6phos,gppfru~tose16phos})/~8.31451*.29815~1
                I0.00329493,  0.00087222,  0.995833)


        A higher concentration of ATP causes more F16BP to exist at equilibrium.

        11.3  (a) Print out the equation for the standard further transformed  Gibbs energy of formation of the pseudoisomer  group
        consisting of  G6P, F6P, and F16BP symbolically.  Assume that the system contains one mole of the pseudoisomer group.  (b)
        Print out the equation for the corresponding semigrand partition  function r ' ' = exp[-G ' ' /RT].  (c) Calculate the amount of
        ATP bound by the pseudoisomer group at [ATPI = 0.0001 M and [ADP] = 0.01 M and then at [ATP] = 0.01 M and [ADP] =
        0.01 M.  (d)  Make the same calculation for the binding of ADP.

        This should be run when Problem  11.2 is still in the workspace.


        (a) Print out the equation for the standard further transformed  Gibbs energy of formation of the C6 pseudoisomer group

                -8.31451*.29815*Log[Exp[-(gpglucose6phos-
                (gpatp+8.31451*.29815*Log[ATP])+(g~adp+8.31451*.29815*Log~~Pl~~/(8.31451*.29815~1+Exp~
                - (gpfructose6phos-
                (gpatp+8.31451*.29815*Log[ATP])+(gpadp+8.31451*.29815*Log[ADPl))/(8.31451*.29815~1+Exp~
                -
                (gpfructose16phos-2*(~atp+8.31451*.29815*Log~ATP1)+2*(gpadp+8.31451*.29815*Log~~P1~~/
                (8.31451*.29815)11
                               -0.403393  (-461.322  +  2.47897  Log[ADPI  -  2.47897  LOg[ATPI)
                -2.47897  Log[E                                                               +
                     -0.403393  (-458.027  +  2.47897  Log[ADP]  -  2.47897  LOg[ATPI)
                    E                                                               +
                    Power[E,  -0.403393  (-2202.84  +  2  (-1428.93  +  2.47897  Log[ADPI)  -
                        2  (-2292.61  +  2.47897  Log[ATPI))II











                - 2.47897 10g(e-0.403393  (2.47897 log(ADP)-2.47897 log(ATP)-461.322)  +
                      e  -0.403393 (2.47897 log(ADP)-2.47897 10g(ATP)-458.027) +
                                                                                     1
                      e  -0.403393 (2 (2.47897 log(ADP)-1428.93)-2  (2.47897 log(ATP)-2292.61)-2202.84)

         Note that the species concentrations of ATP and ADP are in the exponents

         (b) Print out the semigrand partition function

                gamma=Exp [Log [Exp C-  (gpglucose6phos-
                (gpatp+8.31451*.29815*Log[ATPl)+(g~adp+8.31451*.29815*Log[~P]))/(8.31451*.29815)]+Ex~~
                -(gpfructose6phos-
                -
                (gpatp+8.31451*.29815*Log[ATPl~+(g~adp+8.31451*.29815*Log[ADP]))/(8.31451*.29815)1+Expt
                (gpfructose16phos-2*(~atp+~.31451*.29815*Log[ATP])+2*(gpadp+8.31451*.29815*Log[ADP]~~/
                (8.31451*.29815)111
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