Page 328 - Bird R.B. Transport phenomena
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312   Chapter 10  Shell Energy  Balances and Temperature Distributions in Solids and Laminar Flow

                                                      Fig. 10.8-2.  Heating of a fluid in laminar flow through a cir-
                                                      cular tube, showing  the annular ring over  which the energy
                                                      balance is made.
                                      Fluid inlet
                                     temperature  T^





























                               The  energy  balance  is  obtained  by  summing  these  contributions  and  equating  the
                           sum to zero. Then we  divide  by  2тг Ar  Az to get
                                                                    е.'
                                             ( r e ) \ -  ( г £ > ) |  г + Д г  е \ -  ^zlz-ь
                                                r
                                                               7 zlz
                                                       г
                                                                 ?
                                                  r
                                                   Ar      + '  r  Az    +  PVgT  =  0         (10.8-7)
                                                                            z z
                           In  the limit as  Ar and  Az go  to zero, we  find
                                                                                               (10.8.8)
                           The  subscript  z in g z  has been omitted, since the gravity  vector  is acting in the  +z direc-
                           tion.
                               Next we  use  Eqs. 9.8-6  and  9.8-8  to write  out the expressions  for  the r- and z-compo-
                           nents  of  the combined  energy  flux  vector,  using  the  fact  that the only  nonzero compo-
                           nent  of v  is the axial  component v :
                                                       z
                                                              —  v<LL                          (10.8-9)
                                       e  =  T v  +  q  =  - ^  K
                                       r    n z   r   v  d r      dr
                                       e  = ikpvl)v  + pHv  + r v  + q
                                        z       z     z   zz  z  z
                                                                               dv.
                                                   (p  -  f)v  + C (T  -  T)v  -\2n-±\v -     (10.8-10)
                                                         z    P  p     z       dz   z   dz
                           Substituting  these flux expressions  into Eq. 10.8-8 and using  the fact  that v  depends only
                                                                                         z
                           on  r gives, after  some rearrangement,




                           The  second bracket is exactly  zero, as can be seen  from  Eq. 3.6-4, which  is the z-component
                           of the equation  of  motion for  the Poiseuille flow in a circular tube (here &  = p  — pgz). The
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