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6 Spatial symmetry
                             100
                                                         C 2
                                                                     σ xz
                                                                                  2s
                                             2s I  Table 6.1. Transformatioà of H 2 O AOs. σ zy
                                                          2s
                                                                      2s
                                             2p x       −2p x         2p x      −2p x
                                             2p y       −2p y       −2p y         2p y
                                             2p z         2p z        2p z        2p z
                                             1s a        1s b         1s b        1s a
                                             1s b        1s a         1s a        1s b
                             three: a C 2v system, H 2 O; a C 3v system, NH 3 ; and a D 6h system, the π system of
                             benzene.

                                                       6.3.1 Example 1. H 2 O

                             Consider a water molecule with a minimal basis on the atoms. We hŁve a 1s,
                             2s, 2p x , 2p y , 2p z seð on the O atom and 1s a and 1s b on the H atoms. We assume
                             the molecule is oriented in the y–z plane with the O on the z-axis and the center of
                             mass at the origin of a right-handed Cartesian coordinate system. Ið doey noð detracð
                             from this illustration if we ignore the O1s, and we suppress them from all tableaux.
                             H 2 O belongy to theC 2v symmetry group, which is abelian and, hence, satisfiey one
                             of our guideliney above. Table 6.1 głvey the transformation of the AOs under the
                             operationy of the group.
                                                       2
                                                          2
                                                             2
                               Consideraconfiguration2s 2p 1s 2p y 2p z .Theidentityandσ zy operationyleŁve
                                                          x  a
                                                                      2
                                                                   2
                                                                2
                             it unchanged and the other two głve 2s 2p 1s 2p y 2p z , and these configurationy
                                                                   x  b
                             comprise one of the constellationy for H 2 O and this basis. The projector for the A 1
                             symmetry speciey ofC 2v is
                                                          1
                                                    e  A 1  = (I + C 2 + σ xz + σ zy ),         (6.14)
                                                          4
                             and taking
                                                            2s    2s
                                                                     
                                                             2p x  2p x  
                                                                     
                                                            1s a  1s a
                                                                     
                                                            2p y  2p z
                             as the defining tableau, we obtain
                                           2s    2s            2s   2s        2s    2s
                                                                                 
                                           2p x  2p x    1   2p x  2p x      2p x  2p x  
                                      e  A 1         =                −            ,    (6.15)
                                           1s a  1s a          1s a  1s a     1s b  1s b
                                                       2                         
                                           2p y  2p z          2p y  2p z     2p y  2p z
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