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Section 6.2  Plane Stress                                                  243


                           τ, MPa

                                      60
                                                 (60, 40.3)



                                      (25, 20)
                                           40.3
                                     20
                                        35                      (100.3, 0)
                                                                         σ, MPa
                         0  (19.7, 0)                    2θ n
                                                   2θ s
                                                              (95, –20)




                                             (60, –40.3)

                    Figure E6.2 Mohr’s circle corresponding to the state of stress of Fig. E6.1.

             A negative sign is applied to τ xy for the point associated with σ x , because the shear arrows on
             the same planes as σ x tend to cause a counterclockwise rotation. Similarly, a positive sign is used
             for τ xy when associated with σ y , due to the clockwise rotation. The center of the circle must lie
             on the σ-axis at a point halfway between σ x and σ y :


                                              σ x + σ y
                                  (σ, τ) ctr.  =     , 0 = (60, 0) MPa
                                                 2
                 From the preceding coordinate points, the shaded right triangle shown has a base of 35 and
             an altitude of 20 MPa. The hypotenuse is the radius of the circle and is also the principal shear
             stress:




                                               2
                                                    2
                                       τ 3 =  35 + 20 = 40.3MPa                       Ans.
             The angle with the σ-axis is

                                           20
                                  tan 2θ n =  ,   2θ n = 29.74 ◦  (CCW)               Ans.
                                           35

             A counterclockwise rotation of the diameter of the circle by this 2θ n gives the horizontal diameter
             that corresponds to the principal normal stresses. Their values are obtained from the center
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