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368                                             Chapter 8  Fracture of Cracked Members


                                                                    S                  S


                           P                 P
                                  =                 +
               (a)   K 1               K 2               K 2         —     K 3
                          a
                                                               P
                            b
                                                  S                                    S

                                                                    S                S
                          K 1              K 2
                        2b  2b                              K 2              K 3
                       P    P   P        P
                                   =                +
               (b)                                                   –
                                                          P
                      2a  2a  2a
                                                   S                                 S


            Superposition for either (a) or (b): (t = thickness)
                                                       1                        P
                     K 1 = K 2 + K 2 − K 3 ,  so that K 2 =  (K 1 + K 3 ),  where S =
                                                       2                       2bt
            (a) Single crack in finite-width plate for any α = a/b:
                                                                            √
                              P                √               P          F 3 πα

                     K 1 = F P1 √ ,    K 3 = F 3 S πa,  K 2 =  √    F P1 +
                             t b                             2 t b           2
                     F P1 is F P from Fig. 8.15, and F 3 is F from Fig. 8.12(a).
            (b) Infinite array of collinear cracks, exact solutions for any α = a/b:

                                                                   $                    %
                                                                              !
                                          !
                    P     1                      πα             P       1       1    πα
              K 1 = √ √       ,    K 3 = S  2b tan  ,    K 2 =  √    √      +     tan
                   t b   sin πα                  2            2 t b   sin πα    2     2
            Approximations within 10%: (Note limits for (a) or (b), respectively, below each equation.)
                                             √
                                 P      1      πα             0.89P

                         K 2 =   √    √    +       ,    K 2 =  √
                               2 t b    πα     2              t b
                         (α ≤ 0.32 or 0.38)             (0.12 ≤ α ≤ 0.57 or 0.65)
            Figure 8.23 Superposition to obtain solutions for cases of a single crack (a), or a row of
            cracks (b), loaded on one side. (Arguments of trigonometric functions are in radians.)
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