Page 388 - A First Course In Stochastic Models
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MULTI-SERVER QUEUES WITH POISSON INPUT            383

                where q i = lim j→∞ P (L +  = i). It remains to find the limiting probabilities q i .
                                     j
                These limiting probabilities can be obtained by a simple up- and downcrossing
                argument: the long-run fraction of customers finding k other customers in queue
                upon arrival equals the long-run fraction of customers leaving k other customers
                behind in queue when entering service. This holds for any integer k ≥ 0. For
                k  = 0 we also have that the long-run fraction of arrivals finding k other customers
                in queue equals the long-run fraction of arrivals who find k + c other customers
                in the system. This latter fraction equals the time-average probability p c+k by the
                PASTA property. Hence we find
                                                                 c

                             q i = p c+i  for i = 1, 2, . . .  and  q 0 =  p j .
                                                                j=0
                Interchanging the order of summation in (9.6.10), the result (9.6.9) now follows.


                Asymptotic expansion
                It is also possible to give an asymptotic expansion for 1 − W q (x):

                                 1 − W q (x) ∼ γ e −λ(τ−1)x  as x → ∞,      (9.6.11)
                where
                                                   σ
                                          γ =        c−1
                                              (τ − 1)τ
                with τ and σ as in (9.6.3) and (9.6.4). To prove this result, we fix u with 0 ≤ u < D
                and let x run through (k − 1)D + u for k = 1, 2, . . . . Defining
                                 r                      j
                                        −λ(D−u)  [λ(D − u)]
                         b r (u) =  Q r−j e                for r = 0, 1, . . . ,
                                                   j!
                                j=0
                we have by (9.6.9) that

                           1 − W q (x) = 1 − b kc−1 (u)  for  x = (k − 1)D + u.
                                                                         r
                                                           ∞
                Next consider the generating function B u (z) =  (1 − b r (u))z . Since the
                                                           r=0
                generating function of the convolution of two discrete sequences is the product of
                the generating functions of the separate sequences, it follows that
                                            1         λ(D−u)(z−1)
                                  B u (z) =    − Q(z)e         ,
                                          1 − z
                                    j              c+j
                              ∞
                where Q(z) =  j=0  Q j z . Since Q j =  k=0  p k , we find after some algebra that
                                                                c−1
                                                                       k   c
                                                         e λD(1−z)  p k (z − z )
                                        c−1
                             −c
                            z                  k   c            k=0
                     Q(z) =       P (z) −  p k (z − z ) =           c λD(1−z)  ,
                            1 − z                        (1 − z)(1 − z e    )
                                        k=0
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