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I. Design and Performance of Acid Fractures








            EXAMPLE 1-1                                          EXAMPLE 1-2
            Acid-Fracture Penetration                            Calculation of Effective Acid-Fracture Conductivity

            Assuming that the velocity along an acid fracture, u,,  is given   Estimate the effective conductivity of an acid fracture if the
            by                                                   closure pressure is 7000 psi, the rock embedment strength is
                                   9;                            60,000  psi  and  the  fracture  width  is  0.1  in.  Repeat  this
                            u,  =  -                 ‘   (1-1)   calculation for two bottomhole pressures, 1000 psi and 4000
                                 2 I- wh’
                                                                 psi, respectively.
            where qi is the injection rate, and  is equal to I  for the KGD
            model and 7d4 for the PKN model, show a relationship be-   Solution (Ref. Section 18-4)
            tween acid fracture penetration, +,,  and treatment variables.   Case I (pK , = 1000 psi)
            Using the data in Table I- 1, calculate the acid penetration. The
                                                                                     is
            width of the fracture is already generated through the injection   The effective stress, o’, approximately 6000 psi  (7000 -
            of a polymer pad.                                    1000, using Biot’s constant equal to 1).
                                                                   Therefore, from Eqs. 18-19, 3-158 and 3-155,
            Solution (Ref. Section 18-2.1)                             cI = 1.77 x  108(0.1)2.47  =  6 x  lo5,   (1-4)
            The acid penetration is given by Eq. 18-17, and combination
            with Eq. 1-1 results in
                                                                        c2 = (3.8 - 0.28 In 60,000) x  lo-’
                                9i
                          Xf,  =  - -.   W               (1-2)             = 7.19 x                           (1-5)
                                   8rDeJ:f
                                                                 and
            From Table 1-1 and by converting units into a consistent set,
                                                                                    5  -(7.19  x  10-J)(6000)
                                                                         wk,  = 6x 10 e
                   (20) (2.648~ lo3 cm’//s/BPM)
             Xfil  =                                                         = 8027 md - in.,                 (1-6)
                        (70) (30.48cm/ft)
                   (0.20) (2.54 cm/ in.)  I                      or 670 md-ft.
                                                                   If pllf = 4000 psi, then Eq. 1-6 changes to
                   (8) (I) (4 x      =  4.27  x  lo3 cm,   (1-3)
                                                                                    5  -(7.19  x  10-‘)(3000)
                                                                         wkr  = 6x 10 e
            or 140 ft.
              Obviously, the two controlling variables are the injection     = 6.94 x  lo4 md - in.,          (1-7)
            rate  (usually  qi/h = 0.2  to  0.4 BPM/ft)  and  the  effective
            diffusion coefficient, DeF High-efficiency acids with low Defl   or 5800 md-ft, denoting the significance of  the drawdown
            would result in long acid-fracture penetrations.     pressure and the resulting effective stress on the conductivity
                                                                 of an acid fracture.

               9,   =  20BPM
                                      ~      ~       ~
               w   =  0.20 in.
               h   =  70ft
            I   ~  ~  =  f 4x 10-4cm2/s                     I
                      i
            I  r   =  1 (KGDmodel)                          I

            Table I-1-Treatment  variables for Example 1-1.


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