Page 138 - A Practical Companion to Reservoir Stimulation
P. 138

J. Stimulation of Horizontal Wells








            EXAMPLE J-1
                                                                   Figure J- 1 contains the expected flow rates for the two well
            Deliverability of a Damaged Horizontal Gas Well      lengths, for  a  range  of  skin  effects  (damaged  horizontal
                                                                 well). If the skin effect is equal to zero (no damage), then the
            Estimate the steady-state flow rate for a horizontal gas well   well production rate (for L = 1000 ft) will be approximately 1
            using lengths of  1000 ft and  1500 ft, respectively, and for a   MMSCF/d. For a well with moderate damage (s = 5), the rate
            range of skin effects. Table J-1 contains the relevan!  well and   will be approximately  350 MSCF/d.
            reservoir data.                                        As can be seen for a 1500-ft well, the nondamage produc-
                                                                 tion rate is  1300 MSCF/d  (a gain of 300 MSCF/d over the
            Solution (Ref. Section 19-2)                         1000-ft well). The damaged well would not gain appreciably
            Equation  19-3 is  for  an  oil  well.  (While Eq.  19-3 in  the   over  the  1000-ft  well.  This  is  important  because  lack  of
            textbook is as published by Joshi (SPE 15375,1986;JPT June   stimulation  may  reduce  significantly  the expected  benefits
            1988), it has been shown by Economides et al. (SPE 20717,   from a longer well.
            1990) that it must be augmented. The term 2rW must be re-
            placed by (0 + l)rw.. All calculations  in this volume use this
            correction.)  It  can be  readily  modified  for a gas well,  and   kH  =  0.1 md
            using oilfield units, it becomes
                                                                   ,U   =  0.0219~~
                             kH  (P2 - P$)                       I  h   =  25ft                                  I
            4=
                            (If Y  (12-  (Ll?)'
                                         pll
                1424pzT  n-     L12    + -In                     I  Z   =  0.925                                 I
                                         L   (P+  I)r,,
            where a can be obtained from Eq. 19-2. The skin effect has   I  p   =  5068psi                       I
            been added to the denominator in the usual manner.      T   =  650"R [190°F]
              If L = 1000 ft and since reH = 2107 ft, then from Eq.  19-2,   pwr  =  2000psi
            a = 21 37 ft. Substituting all known variables from Table J-1
            into Eq. J- 1  results in
                                 2591                            I  r,   =  0.229 ft                             I
                            4=
                               2.46 + s                            A    =  320 acres [reH = 21 07 ft]
            The calculation, repeated for L = 1500 ft, leads to a = 2175   Table J-1-Well  and reservoir data for Example J-I.
            ft, and from Eq. J- 1,

                                 259 1
                            q=  ~                       (5-3)
                                1.95 + s

















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