Page 18 - A Practical Companion to Reservoir Stimulation
P. 18

PRACTICAL COMPANION TO RESERVOIR STIMULATION




            EXAMPLE A-3
                                                                          (3.14) (3.068)* (13,200) (4 x
            Calculation of the Permeability of a Tight Reservoir     C=
            from a Short-Duration Pressure Buildup Well Test                      (4) (144) (5.615)
                                                                       =  4.8  x   bbl/psi.                (A-10)
           This example demonstrates the method to estimate the res-
            ervoir  permeability  from  a  very  short-duration  pressure   From Eq.  1-101,
            buildup test. Table A-5 contains the bottomhole pressures for
            this test, while the pertinent well and reservoir data are listed   k=  (3000) (4.8 x   (0.7)   =  0.08md.   (A-11)
            in Table A-6.                                                       (42) (3)

            Solution (Ref. Section 1-3.6)                          Sihce the flow rate before the buildup was 9.5 STB/d, then
            Figure A-6 is a log-log diagnostic plot for this problem, and it   an$tempt  for a “forward” match is shown in Fig. A-7. Taking
            indicates  clearly  that  this  (36-hr) well  test  is considerably   any arbitrary pressure difference (e.g., 3 148 psi), the dimen-
            shorter than would be needed for a semilogarithmic interpre-   sionless pressure is calculated from Eq.  1-2:
            tation or even for a reasonably  unique type-curve matching.      (0.08) (42) (3 148)
              Thus, the method implied by Eq.  1-101 can be employed   PD  =                     z  10.5.   (A-12)
            to estimafe the well permeability. At first, from Fig. A-6, the   (141.2) (9.5) (1.08) (0.7)
            time at the end of wellbore storage effects (re.w.,J can be ex-   The match is made by superimposing the real data graph at
            tracted. This is equal to approximately  3 hr, as indicated by   Ap = 3 148 psi with the type curve atpD = 10.5. As can be seen,
            the separation of the pressure and pressure derivative.   the  beginning  of  the  infinite-acting  behavior  would  have
              Next, the dimensioned wellbore coefficient must be calcu-   started at approximately 200 hr (where the derivative begins
            lated. This is given approximately  by:              to flatten). For an accurate calculation of the permeability, a
                            c =  v,,,   Cf,            04-9)     test duration of a month or more would have been required.
                                                                   No calculation of the skin effect is attempted or is neces-
            and must be in barrels per pounds per square inch (divide ft’   sary. First,  the  permeability  is only  an  estimate  (assuming
            by  5.615). In  Q. A-9, cf is the fluid compressibility  under   zero skin effect in the development ofEq. 1-  101). Furthermore,
            wellbore conditions. Thus.                           such a well is an obvious candidate for hydraulic fracturing,
                                                                 and the skin effect will be bypassed by such a treatment. The
                                                                 technique  employed in this example is intended to provide
                                                                 only a rough estimate. It should never substitute for a prop-
                                                                 erly designed and executed pressure transient test. It should
                                                                 be used as a last resort for wells where proper duration testing
                                                                 is uneconomical or impractical.

            I                       I           I           I

                                                                                                ~
                                                                   dtkl      =  0.406 ft
                                                                             =  3.068 in.
                                                                 1  IH       =  13,200
                                                                   rW

                                                                   P
                                                                 I
                                                                             =  0.7 CP
                                                                                9.5 STBfd
                                                                                1.08 res bbl/STB
                                                                             -  42ft

                                                                 I  Ct       =  1.2 x 1 0-5 psi-’
                                                                 I 4         =  0.17
            I           1   931.7  I            I          1
                                    I
                3.0
            Table A-5-Bottomhole  pressures for Example A-3.     Table A-&Well  and reservoir data for Example A-3.


            A-  8
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