Page 73 - A Practical Companion to Reservoir Stimulation
P. 73
DESIGN AND MODELING OF PROPPED FRACTURES
EXAMPLE E-8
Solution (Ref. Section 8-2.6)
Calculation of the Propped Fracture Width
Equation 8-48 provides the propped fracture width. The areal
Using the results of Example E-7 (cf= 10 ppg) and assuming concentration of proppant inside the fracture C,, is simply
that the total fracture generated has xf= 2500 ft and hf = 200 M 2.38 x lo6 lb
ft, calculate the propped width. Assume that (p,, = 0.33 and c,=i = = 2.38 lb/f?. (E-38)
pp = 165 lb/ft3. 2.~rhf 2 x 2500 x 200
Then, from Eq. 8-46,
(12) (2.38)
wp = = 0.26 in. (E-39)
(1 - 0.33) (165)
E- 13
