Page 69 - A Practical Companion to Reservoir Stimulation
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DESIGN AND MODELING OF PROPPED FRACTURES
EXAMPLE E-5
Calculation of Width Using a Non-Newtonian Fluid Substituting the given variables in Table E-3, Eq. E-17
results in
Calculate the width of a hydraulic fracture using the reservoir = 12 [( 13.59) (1.75) (3.33)0'75
variables in Table E-3 but with a fracturing fluid with w,,,
K'=6x lo-' Ibf sec"'/ft*and n'=0.75.
(0.0068) (0.0935) 0.75 ] o.286
Solution (Ref. Section 3-3.4.3)
The maximum fracture width calculated for a non-Newtonian
fluid is given by Eqs. 3-72 and 3-62. In the units given in
Table E-3, Eqs. 3-72 and 3-62 yield
= 0.4in. (E- 18)
The average width would be multiplied by 0.59, as in Example
E-4; i.e., w = 0.24 in.
I
(E- 17)
where the width is in inches.
E-9
