Page 71 - [B._MURPHY,_C._MURPHY,_B._HATHAWAY]_A_working_meth
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Equilibrium I.                                            55

                 ADVANCED EQUILIBRIUM PROBLEMS-
                           WORKING METHOD

       In the previous section, buffer type problems were introduced, where
       the equilibrium expression involved K,, the dissociation constant of an
       acid:
       i.e. HA + H20 + H30+ + A-, Ka  = {[H30'][A-]}/[HA],
       from which the pH of the buffer solution could be determined, using
       the  equation  pH  = -loglo[H30+].  The  following  working  method
       deals  with  acid/base equilibrium  type  problems,  where it has  to  be
       determined whether (a) acid or base dissociation (K, or Kb) occurs, or
       (b) anion  or cation hydrolysis (Kh) occurs.  Such problems  are more
       difficult and need to be divided into a series of steps:

         1. Read the question carefully.
         2.  Identify the type of reaction, i.e. acid/base.
         3. Identify the type of reactants:

                                        3. HC104  4. HZS04
        2. Weak acidi:  1. HN02  2. HC102  3. Carboxylic acids: RC02H
        3. Strong bases:  1. NaOH  2. KOH
        4. Weak bases:  1. NH3   2. Arnines: 1" (RNHZ), 2" (R2NH), 3" (R3N)
         4. Write a balanced equation  for the reaction.  A Bronsted-Lowry
            acid (HfA-)  is  a  proton  donor (Hf) and  a  Bronsted-Lowry
            base (B) is a proton acceptor:
            i.e.     HA     +     B      -+     BH+  +       A-
                     Acid         Base          Cation       Anion
              (donates H+)     (accepts H +)
          5.  Determine  the  amount  of  each  reactant  (expressed  in  moles)
            present initially (the amount of product is zero at this stage).
            bount (in moles) = [Volume (in cm3)x Molarity (in M)]/1000( (*)

         6. Determine  the amount  (in moles)  of reactants  and products  at
            the end of the reaction.
         7.  Calculate  the  concentration  (i.e. molarity)  of  all  species left  in
            solution, from (*), i.e. Molarity (in M)  = [Amount (in moles) x
            1000]/Volume (in cm3)]. However, the  volume now involved is the
            total volume!
          8.  Determine next which of these species has the greatest concentra-
            tion. This then undergoes the equilibrium reaction:
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