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Equilibrium 11                                            59

                           POLYPROTIC ACIDS
       Polyprotic  acids  are  acids  which  have  more  than  one  replaceable
       proton.  Examples include  H2SO4  (eA  =  2),  H3P04 (eA  =  3),  etc.,
       where eA is the number of replaceable hydrogens. Therefore, sulfuric
       acid, H2S04, has two dissociation constants,  Ka(1) and Ka(2) respec-
       tively, corresponding to the following reactions:

       H2SO4 + H20 + H30+ + HSO,,  where Ka(1)  = {[H30'][HSO,])/
       [H2SO4] = 1.3 x      and HSO;  + H20 + H30f  + SO:-,  where
       Ka(2)  = {[H3O'][SO:-])/[HSO,]   = 6.3  x   . AS expected, Ka(2)
        = 6.3 x     < Ka(l) = 1.3 x lov2 , since HSO;  is a relatively weak
       acid and is negatively charged.

                         SOLUBILITY PRODUCT
       In precipitation  reactions,  slightly soluble products  often  form,  and
       there is an equilibrium between the solid and the ions of the saturated
       solution,  e.g.  for  the  reaction  AgCl,,)  + Ag+(aq) +  Cl-(aq),  the
       forward reaction is a dissolution reaction, and the back reaction is a
       precipitation  reaction  + K,  =  { [Ag + (aq)][Cl-(aq)])/[AgCl(s)]. But,
       since the  activity, a, of  a  solid  is unity,  this means  the  equilibrium
       constant can  be  expressed  as Ksp  =  [Ag+(aq)][Cl-(aq)], where  Ksp is
       termed the solubility product. Likewise for the reaction Mg(OH),,,)  +
       Mg2+(aq) + 20H-(aq), Ksp = [Mg2+][OH-I2, etc.



                    Solubility Product Equilibrium Problems

         Example No. 1: The solubility product of calomel, Hg2C12 is 1.1 x
       I  10-l8. Determine the molar solubility of Hg2C12.
                          ~
       Solution:
          1. Solubility product question!
         2.  Hg2Cl2,,)  i= HgZ,+(aq) + 2C1-(aq)-Heterogeneous  equilibrium (2
            phases).
          3.  ~sp [~g:+(aq~cl-(aq)~~-
                =
         4.             Hg2C12,s)  'C  H&+(aq)  +  2Cl-(aq)
            Initial conc.            0            0
            Change                    +X          + 2x
            Final conc.               +X          + 2x
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