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592    CHAPTER 16  The Wave Equation



                                                     1.6


                                                     1.2


                                                     0.8



                                                     0.4


                                                      0
                                                        0    0.2    0.4   0.6    0.8    1
                                                                        x

                                                     FIGURE 16.9 Profiles of the elastic bar at dif-
                                                     ferent times with f (t) = K.

                                                         g(t)


                                                   (0, 2L/c)




                                                                                          t
                                                                   (4L /c, 0)  (8L /c, 0)


                                                   FIGURE 16.10 Sawtooth wave.



                                 The interesting thing about this is that this function has a simple inverse transform. Let g be
                                 periodic of fundamental period 4L/c, with g(t) for 0 ≤ t ≤ 4L/c defined by


                                                               t     for 0 ≤ t ≤ 2L/c,
                                                        g(t) =
                                                               4L/c  for 2L/c ≤ t ≤ 4L/c.
                                 A graph of this sawtooth wave is shown in Figure 16.10.
                                    Thus the right end of the bar moves according to the graph of g, exhibiting an up-and-down
                                 oscillation.

                                 Case 2 Another case in which we can do a fairly complete analysis is that the end is hit with
                                 an impulse of magnitude I at time zero. Suppose f (t) = Iδ(t), with δ the delta function. The
                                 analysis proceeds as in case 1, except now we obtain

                                                                    cI sinh(sx/c)
                                                            Y(x,s) =             ,
                                                                    E s cosh(sL/c)
                                 differing from case 1 in the power of s in the denominator. This occurs because the Laplace trans-
                                 form of K is K/s, while the transform of Iδ(t) is just I, the delta function having transform 1.
                                 Since






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                                   October 14, 2010  15:23  THM/NEIL   Page-592        27410_16_ch16_p563-610
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