Page 491 - Advanced Organic Chemistry Part B - Reactions & Synthesis
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464               5.4. Predict the stereochemistry of the products from the following reactions and
                           justify your prediction.
      CHAPTER 5
      Reduction of
      Carbon-Carbon Multiple
      Bonds, Carbonyl
      Groups, and Other    (a)  O  O     KBH                 (b)  CH 3  O
      Functional Groups              CH 3   4                  H        LiAlH 4
                                          2
                             O    O  CH 3  H O                  Ph   Ph  Et O
                                                                          2
                           (c)  H  O                         (d) (CH ) CH       Pt, H
                                                                  3 2
                                     LiBHEt                                        2
                                         3                                     ethanol
                                                                   HO       CH 3
                                H
                           (e)       OTHP                    (f)    C(CH )
                                  H 3 C                                3 3
                                             H                               H 2
                                              2
                                                                           Rh/Al O
                                           (PPh ) RhCl                        2  3
                               C             3 3
                             H 2                               CH      CH 3
                                    CH 3                         3
                                  O CCH                             OH
                                   2  3
                           (g)  C                            (h)        O
                               H 2
                                                                    CH 3
                                   O        H , Pd                         O
                             HO        OCH 3  2                              H /Pd – C
                                                                              2
                                                               O
                                HNCCH                              CH
                                     3                               3
                                  O
                           (i)        OCH OCH                (j)   CH
                                         2  3                        3
                                                                                   P
                                                                           [NBD  Rh  ] 1+
                             PhCH O               Zn(BH ) 4 2                      P
                                2                                       OH
                                        O
                               CH OCH O         OMe
                                3   2
                           (k)               LiAlH           (l)      CH
                             CH (CH ) C  CCH 2 OH  4                    3
                               3  2 4
                                             ether
                                                                           [(C H ) P – Ir(COD)py]PF
                                                                        OH   6  11 3      6
                                                               CH              H , CH Cl
                                                                 3              2  2  2
                           (m)  O                            (n)
                                                                     H  N
                                                                                 11 3
                                                                               6
                             PhCHCCH CH 3  L-Selectride                      [(C H ) P – Ir(COD)py]PF 6
                                   2
                                                                    N      O      H , CH Cl
                              CH 3                                                2   2  2
                                                                    H     CO
                                                                       CH 3
                                                                            2
                           (o)       OCH CH 3 O TBDMSO       (p)  CH 3  O
                                  OCH   3            O
                                     3
                             O N                                      N
                              2                                             [(C H ) P – Ir(COD)py]PF
                                                       NOCH                   6  11 3      6
                                                           3
                                          O     CH         ZnBH     CH Ph        H 2 , CH 2 Cl 2
                                       CH    CH 3  3  CH CH   4       2  CH OCH 3
                                                                           2
                                        3             3  3
                                  OCH
                                     3
                           (q)      O
                                               ZnCl
                                            H     2
                                         CO 2
                                      CH 3     DiBAlH
                        5.5. Suggest a convenient method for carrying out the following syntheses. The
                           compound on the left is to be made from the one on the right (retrosynthetic
                           notation). No more than three steps should be necessary.
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