Page 138 - Advanced Thermodynamics for Engineers, Second Edition
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6.2 EFFICIENCY AT MAXIMUM POWER          125





                  Substituting in Eqn (6.8) gives

                                              U H A H T H ðs   T C =T H Þ
                                        T 2 ¼                  þ T C ;
                                                        U H A H
                                               U C A C 1 þ
                                                         U C A C

                                              U H A H T H s   s 2
                                           ¼                þ T C ;                         (6.16)
                                              ðU C A C þ U H A H Þ
                                                 (       1=2        1=2 )
                                               1=2 U H A H T  þ U C A C T
                                           ¼ T           H          C
                                               C
                                                      U H A H þ U C A C
                  Similarly,
                                                (       1=2        1=2  )
                                              1=2 U H A H T H  þ U C A C T C
                                        T 1 ¼ T                        :                    (6.17)
                                              H
                                                      U H A H þ U C A C
                  To be able to compare the effect of varying the resistances, it is necessary to maintain the total
               resistance to heat transfer the same. For example, let

                                                U H A H þ U C A C ¼ 2:
                         U H A H
                  Then, if     ¼ 1 (as in the previous example), U H A H ¼ 1.
                         U C A C
                  Consider the effect of having a high resistance to the high temperature reservoir, e.g. U H A H /
               U C A C ¼ 1/2.
                  This gives
                                                         2      2
                                              U H A H ¼       ¼ :
                                                         U C A C  3
                                                     1 þ
                                                         U H A H
                  Then,
                          W _       ð1=2   1=4Þ
                                                                           _
                             ¼ 1600           ð1   1=2Þ¼ 267 units;  giving  W ¼ 177:8 units:
                        U H A H     ð1 þ 1=2Þ=2
                                            _
                                Q _  H     W
                                                                   _
                                    ¼             ¼ 534 units  and  Q ¼ 355:6 units:
                                                                    H
                               U H A H  U H A H ð1   sÞ
                  Then,
                        Q _ C   Q _ C  1  1
                                                     _
                                                                           _
                                                _
                            ¼      $ ¼         Q   W ¼ 133:5 units; giving Q ¼ 177:8 units
                                                 H
                                                                            C
                       U C A C  U H A H 2  2U H A H
                  Hence,
                                  1
                              T 1 ¼ ð133:5 þ 400Þ¼ 2   533:5 ¼ 1067 K; and T 2 ¼ 533:5K:
                                  s
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