Page 347 - Advanced engineering mathematics
P. 347

10.5 Applications and Illustrations of Techniques  327


                                        Now use the initial condition to solve for the constants. Solve
                                                                    ⎛ ⎞   ⎛                  ⎞
                                                                     4         5c 2 + 10c 3 + 9
                                                                        =      c 1 + c 3 − 18/5  .
                                                             i(0+) = 4 ⎠  ⎝                  ⎠
                                                                    ⎝
                                                                     0      c 1 − 4c 2 − 9c 3 − 18/5
                                        This can be written as
                                                                 0  5    10            −5
                                                               ⎛           ⎞         ⎛     ⎞
                                                               ⎝ 1  0    1 ⎠  C = PC = 38/5 ⎠  .
                                                                                     ⎝
                                                                 1  −4 −9              18/5
                                        Then
                                                           ⎛    ⎞      ⎛             ⎞⎛     ⎞   ⎛     ⎞
                                                             −5      1   4    5    5     −5       18/5
                                                    C = P −1  ⎝ 38/5 ⎠  =  ⎝ 10  −10  10 ⎠⎝ 38/5 ⎠  =  ⎝ −9 ⎠ .
                                                                    10
                                                            18/5        −4    5    −5    18/5      4
                                        The current is
                                                                    ⎛      −2t     −20t/9  ⎞
                                                                     9 − 4te  + 40e
                                                                 i =  ⎝    4e −20t/9  ⎠ .
                                                                       36e −2t  − 36e −20t/9




                               SECTION 10.5        PROBLEMS



                             1. Referring to the circuit of Figure 10.4, determine how  pound of salt per gallon, tank 1 initially has 200
                               much time elapses between the time the switch is  pounds of salt, and tank 2 initially has 150 pounds
                               closed and the time the charge on the capacitor is  of salt. Determine the amount of salt in each tank at
                               a maximum. What is the maximum voltage on the  time t > 0.
                               capacitor?
                                                                           3. Two tanks are connected as shown in Figure 10.6.
                             2. Referring to Figure 10.5, tank 1 initially contains 200  Tank 1 initially contains 100 gallons of water in which
                               gallons of saltwater (brine), while tank 2 initially con-  40 pounds of salt are dissolved. Tank 2 initially con-
                               tains 300 gallons of brine. Beginning at time 0, brine  tains 150 gallons of pure water. Beginning at t = 0, a
                               is pumped into tank 1 at the rate of 4 gallons per  brine solution containing 1/5 pound of salt per gal-
                               minute, pure water is pumped into tank 2 at 6 gallons  lon is pumped into tank 1 at the rate of 5 gallons
                               per minute, and the brine solutions are interchanged  per minute. At this time, a solution which also con-
                               between the two tanks and also flow out of both tanks  tains 1/5 pound of salt per gallon is pumped into
                               at the rates shown. The input to tank 1 contains 1/4  tank 2 at the rate of 10 gallons per minute. The


                                                    Brine 4 gal/min        12 gal/min         Water 6 gal/min





                                                              Tank 1                    Tank 2


                                                                                                  6 gal/min

                                                    4 gal/min             12 gal/min
                                                   FIGURE 10.5 Connected tank system for Problem 2, Section 10.5.





                      Copyright 2010 Cengage Learning. All Rights Reserved. May not be copied, scanned, or duplicated, in whole or in part. Due to electronic rights, some third party content may be suppressed from the eBook and/or eChapter(s).
                      Editorial review has deemed that any suppressed content does not materially affect the overall learning experience. Cengage Learning reserves the right to remove additional content at any time if subsequent rights restrictions require it.

                                   October 14, 2010  20:32  THM/NEIL   Page-327        27410_10_ch10_p295-342
   342   343   344   345   346   347   348   349   350   351   352