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78                                           3 Basics of Gas Combustion

              Then the mole fraction of each species is determined as follows:

                    y CO ¼ 0:17; y NO ¼ 0:03; y CO2 ¼ 0:29; y O2 ¼ 0:30; y N2 ¼ 0:21:


            3.3.4 The Pseudo-Steady-State Approximation


            Many combustion reactions involve free radicals, which are very reactive inter-
            mediate species. They are consumed rapidly and present at very low concentration,
            but are critical to the combustion reactions. It is important to understand how they
            affect the chemical equilibrium and overall rate of constant.
              Consider an overall reaction A ! B þ C, which proceeds through the free
            radical of A*. Molecules of A first collide with other molecule (M) that does not
            change, to produce free radicals A*, followed by decomposition of A to B þ C.

            These two step reactions can be described as follows:
                                           k f 1

                                      A þ M $ A þ M                         ð1Þ
                                           k b1

                                           k 2

                                        A ! B þ C                           ð2Þ
              Note that the first reaction is reversible and the second is one way. The rate of

            reaction before reaching equilibrium in terms of A for the first reversible reaction is

                                     ½
                              d A½Š  d A Š

                                  ¼     ¼ k f 1 A½Š M½Š þ k b1 ½A нMŠ   ð3:39Þ
                               dt    dt

              And for the second step, A is consumed only and the corresponding rate is

                                      d½A Š

                                           ¼ k 2 ½A Š                    ð3:40Þ
                                        dt

              The overall consumption rate of [A ] considering both reactions is

                            d A Š
                             ½


                                 ¼ k f 1 A½Š M½Š þ k b1 ½A нMŠ  k 2 ½A Š  ð3:41Þ
                             dt
              Since A* is so reactive that it is consumed almost immediately after its forma-
            tion; this is referred to as the pseudo-steady-state approximation [7]. Thereby,
            mathematically, the left hand side of the above equation is zero, and it becomes
                              k f 1 A½Š M½Š   k b1 ½A нMŠþ k 2 ½A м 0  ð3:42Þ
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