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380                                        12  Carbon Capture and Storage

              The average speed in the pipe can be determined using

                                4 _ m    4   111
                           U ¼      ¼               ¼ 1:007 m=s
                               qpd 2  877   p   0:4 2
            The corresponding Reynolds number is determined using Eq. (12.63).

                             4 _ m       4   111                  6
                       Re ¼     ¼                      ¼ 4:57   10
                            lpd   7:73   10  5    p   0:4
                                                         6
            With e ¼ 4:6   10  5  m, d ¼ 0:4 m and Re ¼ 4:57   10 , the Darcy friction factor
            can be determined using Eq. (12.62) as follows:

                                                 !
                           1            e    2:51

                         f D  2  ¼ 2 log 10  þ  1
                                       3:7d     2
                                             Ref
                                                D
                                                             !
                                       4:6   10  5    2:51
                            ¼ 2 log             þ
                                    10                      1
                                        3:7   0:4         6 2
                                                  4:57   10 f D
                                                               !
                                                    5:492   10  5
                            ¼ 2 log 10  3:108   10  5  þ  1
                                                         f  2
                                                         D
              By iteration, we can get f ¼ 0:0217.
                                   D
              Then we can calculate the pressure drop over 100 km distance length using
            Eq. (12.61).
                                2
                             qU
                     DP ¼ f D     DL
                              2d
                                           2
                                 877   1:007           3          6
                        ¼ 0:0217               100   10 ¼ 2:41   10 Pa
                                   2   0:4
            So the pressure drop is about 2.41 MPa over a distance of 100 km. Due to this kind
            of great resistance, intermediate pumping (or booster) stations are required at cer-
            tain intervals along the pipeline.
              We have to be careful that the CO 2 properties are assumed constant in the above
            example in order to simplify the calculation. In reality, they cannot remain constant.
            Glilgen et al. [25] experimentally determined the pressure, density, and temperature
            relationship of CO 2 in the homogeneous region for pressures up to 13 MPa and
            temperatures in the range of 220–360 K. For P < 9 MPa and T > 298 K, CO 2
            density varies considerably with P and T.
              In the engineering practice, it is critical to ensure enough pressure to maintain
            above vapor–liquid equilibrium conditions to avoid liquid slugs and other opera-
            tional problems resulted from a two-phase (gas–liquid) flow. A typical operating
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