Page 189 - Air and Gas Drilling Manual
P. 189

354 696
                                      r =
                                       c
                                           14 696
                                      r = 24 14. . .   Chapter 5: Shallow Well Drilling Applications    5-31
                                       c
                               The approximated derated output pressure, p d2, for this  compressor when placed at a
                               6,000 ft surface drilling location is determined from
                                      p d2  =  r p at
                                             c
                               where p at is  the actual atmospheric pressure at the 6,000  ft surface drilling  location
                               (i.e., 11.679 psia).  Thus, the derated output pressure, p d2, is
                                                   11 769)
                                      p   = ( 24 14) ( .
                                               .
                                       d2
                                      p d2  =  284 1 psia
                                               .
                                   The above compressor derated pressure of 284.1 psia is greater than the injection
                               pressure of 96.2 psia, therefore, the compressor is capable of producing the injection
                               pressure needed for this example drilling operation.
                                   The last criteria to consider is whether the prime mover has the power to  operate
                               at the 6,000  ft surface elevation.   The prime mover for this  compressor is  a  diesel
                               fueled, turbocharged, Caterpillar Model 3406 with a peak output  of 400 horsepower
                               at 1,800 rpm (at API standard conditions) (see Section 4.7).
                                                             ˙
                                   The theoretical shaft horsepower,  W ,  required  by  the  compressor  is  obtained
                                                             s
                               from Equation 4-35a.  Equation 4-35a becomes
                                                                       (. )   
                                                                        04
                                            2
                                                    11
                                               1 4
                                            () ( . ) (.769 ) (840 )     284 1  ()( . )  
                                                                    . 
                                                                          4
                                                                        21
                                       ˙
                                      W =                                   − 1
                                        s
                                             (.)      229 .17     11 .769   
                                              04
                                                                              
                                       ˙
                                      W = 173 .9
                                        s
                               Assuming a mechanical efficiency, ε , is
                                                          m
                                      ε m  = 090
                                            .
                                                                             ˙
                               Then  from  Equation  4-39,  the  actual  shaft  horsepower,  W ,  required  by  the
                                                                              as
                               compressor is
                                      W ˙  as  =  173 .9
                                              . 09
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