Page 193 - Air and Gas Drilling Manual
P. 193

Equation 5-5 becomes
                                                                     2
                                                                    
                                                     Chapter 5: Shallow Well Drilling Applications    5-35
                                                                    
                                      f =            1            
                                                  .
                                                          .
                                                
                                          2 log   0 396  − 0 198  + 114 
                                                                  .
                                                  0 0040         
                                                      .
                                      f = 0 049
                                           .
                               Equations 5-2 and 5-3 become, respectively,
                                      a a  =   10 .     1  +   0 192.    
                                                 
                                                            
                                            53 36     0 700.  
                                              .
                                            .
                                      a a  = 0 024
                               and                                                 2
                                                                               0 700)
                                                   .
                                     b a  =       0 049         53 36.    2  (.
                                                                       π
                                            (
                                               .
                                                   .
                                           2 32 2) ( 0 396  − 0 198.  )   10.       2  [  2  2 ] 2
                                                                            0 396)
                                                                                     (.
                                                                         (.      − 0 198)
                                                                       4
                                      b a  = 627 5
                                              .
                                   The  bottomhole  temperature  is  determined  from  the  surface  geothermal
                               temperature rock formations at the surface, the geothermal gradient, and the depth of
                               the borehole.  The geothermal temperature of the rock formations near the surface is
                               assumed to be represented by the temperatures given in Table 4-1 (also see Appendix
                               D).  Thus, for a 6,000 ft surface location this  temperature is  assumed to  be 37.6˚F.
                               For this  example the geothermal gradient is  approximated  to  be  0.01˚F/ft.    Thus,
                               T bh, is
                                              o
                                      t r  = 37 6 F
                                             .
                                      T =  t + 459 67.
                                       r
                                            r
                                      T = 497 27.  o R
                                       r
                                      T bh  =  T + 0 01 1 200.  ( ,  )
                                             r
                                                 o
                                              .
                                      T bh  = 509 27 R
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