Page 198 - Air and Gas Drilling Manual
P. 198

5-40    Air and Gas Drilling Manual
                               This will give a volumetric flow rate to  the drilling  operation of 1,400  acfm (factor
                               of safety of 1.51).
                                   A comparison must also be made between the injection pressure required to  drill
                               this borehole and the pressure capability of this  compressor.  The injection pressure
                               is obtained by a sequence of calculation steps that determine the bottomhole pressure
                               in the annulus, the pressure at the bottom  of the inside of the drill  string,  and then
                               the  injection  pressure  (upstream  through  the  circulation  system).    In  these
                               calculations, the actual volumetric flow rate through each of the two compressors is
                               700  acfm.    Also,  in  these  calculations,  the  actual  atmospheric  conditions  at  the
                               drilling  location  will  be  used  (i.e.,  12.685  psia  and  40˚F)  (see  Table  4.2  or
                               Appendix D).  The atmospheric pressure of the air, P at, entering the compressor is
                                             .
                                      p at  = 12 685 psia
                                      P at  =  p 144
                                             at
                                                   2
                                      P at  = 1 827 lb/ft abs
                                            ,
                               The atmospheric temperature of the air, T at, entering the compressor is
                                             o
                                      t at  = 40 F
                                                   .
                                      T at  =  t at  + 459 67
                                                 o
                                              .
                                      T at  = 499 67 R
                               Thus, P g and T g become

                                      P =  P at  = 1 827 lb/ft abs
                                                         2
                                                 ,
                                       g
                                      T =  T at  = 499 67 R
                                                      o
                                                   .
                                       g
                               Using  Equation  4-11,  the  specific  weight  of  the  atmospheric  air  entering  the
                               compressor is
                                             (1 827,  ) (1 0.  )
                                      γ  =
                                       g
                                            (53 36.  ) (499 67.  )
                                      γ g  = 0 0690 lb/ft 3
                                            .

                               The volumetric flow rate of air entering the top  of the drill  string (and entering the
                               two compressors), Q g, is
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