Page 116 - Aircraft Stuctures for Engineering Student
P. 116

100  Energy methods of structural analysis


                          -ve  B.M. (Decreasing Curvature)



                                                                       0.187 M,
                                                                        2






                                                               moment M,






                                  (a)                                   (b)
             Fig. 4.22  Distribution of bending moment in frame of Example 4.7.


             In fact, the question of whether a structure possesses linear or non-linear character-
             istics arises only after the initial step of writing down expressions for the total poten-
             tial or complementary energies. However, a great number  of  structures are linearly
             elastic and possess unique properties which enable solutions, in  some cases, to  be
             more easily obtained. The remainder of this chapter is devoted to these methods.





             In  Section  4.6  we  discussed  the  dummy  or fictitious  load  method  of  obtaining
             deflections of structures. For a linearly elastic structure the method may be stream-
             lined as follows.
               Consider the framework of Fig. 4.7 in which we require, say, to find the vertical
             deflection of the point C. Following the procedure  of  Section 4.6 we would place a
             vertical dummy  load  Pf at C and  write down  the  total complementary  energy of
             the framework, viz.
                                   k            n
                                        Xi dFi -   Alpr                (See Eq. (4.15))
                                  i= 1         r=l
             For a stationary value of C

                                                                                (4.24)

             from which

                                               dFi
                                     A,  = c -  as before                       (4.25)
                                             Xi
                                          i=  1   apf
   111   112   113   114   115   116   117   118   119   120   121