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5.6 Energy method for the bending of thin plates  143

              rotation, of the ends of the element is negative as the slope decreases with increasing x.
              The bending strain energy due to M, is then

                                          1
                                         -Mx6Y(  -ssx)
                                                   a2W
                                         2
              Similarly, in the yz plane the contribution of My to the bending strain energy is

                                          1
                                         -M,,SX  ( $ )
                                                  --sy
                                          2
              The strain energy due to the twisting moment per unit length, Mxy, applied to the by
              edges of the element, is obtained from Fig. 5.14(b). The relative rotation of the by
              edges is (#w/axay)sx  so that the corresponding strain energy is





              Finally, the contribution of the twisting moment Mxy on the Sx edges is, in a similar
              fashion
                                           1       @W
                                           - MXYSX -
                                                       6y
                                           2      axay
              The total strain energy of the element from bending and twisting is thus
                                       a2w      a2W
                               1 ( - M,    - My@  + 2Mxy- axay  ) sxsy
                               2

              Substitution for M,, My and Mxy from Eqs (5.7), (5.8) and (5.14) gives the total strain
              energy of the element as





              which on rearranging becomes





              Hence the total strain energy U of the rectangular plate a x b is





              Note that if the plate is subject to pure bending only, then M,,  = 0 and from Eq.
              (5.14) @w/axay = 0, so that Eq. (5.37) simplifies to
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