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146  Bending of thin plates























                   Fig. 5.1 6  Calculation of shear strain corresponding to bending deflection.


                   (aw/dy)Sy and the angle DC2Cl  is awlax. Thus C1D is equal to
                                                   aw aw
                                                   --
                                                   ax aybY
                   and  the  angle DACl  representing the  shear  strain corresponding to the  bending
                   displacement w is
                                                    aw aw
                                                    --
                                                    ax ay
                   so that the work done on the element by the shear force NxySx is
                                                 1     aw aw
                                                 - NXySx - -
                                                 2      ax ay
                   Similarly, the work done by the shear force Nxy6y is
                                                 1     aw aw
                                                 -N  S --
                                                 2  xy  yax ay
                   and the total work done taken over the complete plate is




                   It follows immediately that the potential energy of the Nxy loads is
                                                          awaw
                                         V  =-'r/ 2Nxy--         dx dy                (5.44)
                                          xy    2  0  0    ax ay
                   and for the complete in-plane loading system we have, from Eqs (5.42),  (5.43)  and
                   (5.44),  a potential energy of

                                                 +
                          v = -'rr 200 [.. ( g)2 Ny( $)2  +        ax ay              (5.45)
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