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1.12 Determination of strains on inclined planes  21

            Further, by  substituting E,  = yxz = yyz = 0 in the six equations of  compatibility
          and noting that E,,   E,  and y,,  are now purely functions of x and y, we are left with
          Eq. (1.21), namely
                                       2     d2&,
                                      8 TXY  -     @E,
                                      axay   ax2 +ay2

          as the only equation of compatibility in the two-dimensional or plane strain case.





          Having defined the strain at a point in a deformable body with reference to an arbi-
          trary system of coordinate axes we may calculate direct strains in any given direction
          and the change in the angle (shear strain) between any two originally perpendicular
          directions at that point. We shall consider the two-dimensional case of plane strain
          described in Section 1.1  1.
            An element in a two-dimensional body subjected to the complex stress system of
          Fig.  1.13(a) will  distort  into  the  shape  shown  in  Fig.  l.l3(b).  In  particular,  the
          triangular element ECD will suffer distortion to the shape E’C‘D’ with corresponding
          changes in the length FC and angle EFC. Suppose that the known direct and shear
          strains associated with the given stress system are E,,   E,  and yxy (the actual relation-
          ships will be investigated later) and that we  require to find the direct strain E,  in a
          direction normal  to  the  plane  ED and  the  shear strain y produced  by  the  shear
          stress acting on the plane ED.
            To a first order of approximation

                                   C’D’ = CD( 1 + E,)
                                    C’E’ = CE( 1 + E~)                       (1.29)
                                   E’D‘ = ED(1 + ~,+,p)

                       ~
          where  E  ~  +  is   /the  direct strain  in  the  direction ED.  From  the  geometry of  the
                          ~
          triangle E’C’D’ in which angle E’C’D’ = 7r/2 - y,,
                                         I  ‘2
                     (E’D’)2 = (C’D’)2 + (C E )  - 2(C’D’)(C’E’) COS(T/~ - yXy)

          Y                                      Y














          Fig. 1.13  (a) Stress system on rectangular element; (b) distorted shape of element due to stress system in (a).
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