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SINGLE-CHANNEL QUEUING MODEL WITH POISSON ARRIVALS AND ARBITRARY SERVICE TIMES  471



                                        Single-Channel Queuing Model with Poisson Arrivals
                                11.7
                                        and Arbitrary Service Times

                                      Let us return to the single-channel model where arrivals are described by a Poisson
                      When providing input to  probability distribution. However, we now assume that the probability distribution
                      the M/G/1 model, be  for the service times is not an exponential probability distribution. Thus, using the
                      consistent in terms of the  Kendall notation, the queuing model that is appropriate is an M/G/1 model, where G
                      time period. For example,
                      if l and   are expressed  denotes a general or unspecified probability distribution.
                      in terms of the number of
                      units per hour, the  Operating Characteristics for the M/G/1 Model
                      standard deviation of the
                      service time should be  The notation used to describe the operating characteristics for the M/G/1 model is:
                      expressed in hours. The
                      example that follows                ¼ the mean arrival rate
                      uses minutes as the time
                      period for the arrival and          ¼ the mean service rate
                      service data.                       ¼ the standard deviation of the service time
                                      Some of the steady-state operating characteristics of the M/G/1 waiting line model
                                      are as follows:
                                         1 The probability that no units are in the system:



                                                                      P 0 ¼ 1                         (11:24)



                                         2 The average number of units in the waiting line:


                                                                        2 2
                                                                           þð = Þ 2
                                                                   L q ¼                              (11:25)
                                                                        2ð1    = Þ

                                         3 The average number of units in the system:




                                                                      L ¼ L q þ                       (11:26)


                                         4 The average time a unit spends in the queue:



                                                                            L q
                                                                       W q ¼                          (11:27)


                                         5 The average time a unit spends in the system:


                                                                              1
                                                                      W ¼ W q þ                       (11:28)







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