Page 302 - Analysis and Design of Machine Elements
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Analysis and Design of Machine Elements
                   280
                        Steps          Computation                                   Results     Units
                        (4) Circumfer-  According to d VI  and Table 4.1, the dimension of a key is  Key for gear
                        entially       selected as b × h × l = 20 × 12 × 40 mm. Meanwhile, to ensure  20 × 12 × 40
                        locating       better concentricity between the gear hub and shaft, the fit  H7/n6
                        elements on    between the gear hub and the shaft is selected as H7/n6.  Key for
                        the shaft      Similarly, a parallel key used to connect the half coupling and  coupling
                                       the shaft is selected as 14 × 9 × 70 mm, and the fit is H7/k6.
                                                                                     14 × 9 × 70
                                       A light interference fit is selected between the bearing and  H7/k6
                                       shafts. The tolerance of shaft diameter is selected as m6.
                        (5) Determine  Select the shaft chamfer as 2 mm. The fillet radii of shaft
                        the shaft fillets  shouldersare showninFigureE10.2.
                        and chamfers
                                       The initially designed shaft structure is shown in
                                       Figure E10.2.

                        4. Force analysis
                        (1) Determine  Since the reference diameter of the low-speed stage gear is  F = 4558  N
                                                                                      t
                        the forces     d =  m z  =  3 × 108  = 331.739mm             F = 1699    N
                                            n
                        acting on the  2  cos     cos 12.4 ∘                          r          N
                        gear              2T   2 × 7.56 × 10 5                       F = 1002
                                                                                      a
                                       F =   =           = 4558N
                                       t   d     331.739
                                           2
                                       Therefore
                                          F tan     4558 × tan 20 ∘
                                       F =  t  n  =       ∘   = 1699N
                                       r
                                           cos       cos 12.4
                                                              ∘
                                       F = F tan    = 4558 × tan 12.4 = 1002N
                                            t
                                       a
                                       The directions of tangential force F , radial force F and axial
                                                               t
                                                                          r
                                       force F are shown in Figure E10.3.
                                           a
                        (2) Forces on  Forces acting on the gear are assumed to act at the midpoint  R H1  = 1461  N
                        the shaft      of the face width. Select the value for the effective reaction  R  = 3097  N
                                       point as a = 27.4 mm from the bearing catalogues for bearing  H2  N
                                       7313C [12]. According to the previous structural design,  R V1  = 1539  N
                                       decide the spans of L = 118.4 mm, L = 113.6 mm,  R V2  = 160
                                                     1
                                                                2
                                       L = 53.6 mm.
                                       3
                                       Resolve the forces in two perpendicular planes, usually
                                       horizontal plane and vertical plane. Perform free body
                                       diagram analysis for the reaction forces at all supporting
                                       bearings in each plane. Therefore,
                                       Reaction forces in horizontal plane are
                                       R  = 1461 N, R  = 3097 N
                                        H1        H2
                                       Reaction forces in horizontal plane are
                                       R V1  = 1539 N, R V2  = 160 N
                                                                                             (continued)
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